An increase in intensity level of 1dB implies an increase in the intensity by(given $anti{{\log }_{10}}0.1=1.2589$
a) 1%
b) 3.01%
c) 26%
d) 0.1%
Answer
640.5k+ views
Hint: Decibel (dB) is a relative unit of measurement corresponding to one tenth of bel(B). it is given in the question that the intensity level on the decibel scale is by 1dB. Hence we can use the decibel scale i.e. $L=10\log \left( \dfrac{I}{{{I}_{0}}} \right)$ where ${{I}_{0}}$ is the intensity for threshold hearing and I is the intensity corresponding to a particular value on the decibel scale to calculate the increase in intensity when the value on the scale increases by 1dB.
Complete answer:
Let the initial reading on the decibel scale be M. Hence the corresponding intensity i.e. (${{I}_{1}}$) for that is given by,
$M=10\log \left( \dfrac{{{I}_{1}}}{{{I}_{0}}} \right)...(1)$ Now in the question it is given that the value of the scale increases by 1dB, hence the intensity(${{I}_{2}}$) corresponding to that is given by,
$M+1=10\log \left( \dfrac{{{I}_{2}}}{{{I}_{0}}} \right)...(2)$ . Now let us subtract equation 1 from 2
$\begin{align}
& \Rightarrow M+1-M=10\log \left( \dfrac{{{I}_{2}}}{{{I}_{0}}} \right)-10\log \left( \dfrac{{{I}_{1}}}{{{I}_{0}}} \right) \\
& \Rightarrow 1=10\log \left( \dfrac{\dfrac{{{I}_{2}}}{{{I}_{0}}}}{\dfrac{{{I}_{1}}}{{{I}_{0}}}} \right)=10\log \left( \dfrac{{{\text{I}}_{\text{2}}}}{{{\text{I}}_{\text{1}}}} \right) \\
& \Rightarrow \dfrac{1}{10}=\log \left( \dfrac{{{\text{I}}_{\text{2}}}}{{{\text{I}}_{\text{1}}}} \right) \\
& \Rightarrow 0.1=\log \left( \dfrac{{{\text{I}}_{\text{2}}}}{{{\text{I}}_{\text{1}}}} \right) \\
& \Rightarrow \dfrac{{{\text{I}}_{\text{2}}}}{{{\text{I}}_{\text{1}}}}={{10}^{0.1}}=1.26 \\
& \Rightarrow {{\text{I}}_{\text{2}}}=1.26{{\text{I}}_{\text{1}}} \\
\end{align}$
Hence the increase in the intensity is 26%.
Note:
The Decibel scale is used to the ratio of one power to another on a logarithmic scale, The logarithmic quantity being called the power level or field level, respectively. The definition of decibel is based on the measurement of power in telephony of the early 20th century in the bell system in the United states. This was basically named in honor of Alexander Graham Bell.. Today the decibel is used for a wide variety of measurements in science and engineering most prominently in acoustics, electronics etc. In electronics, the gains of amplifiers, attenuation of signals and signal to noise ratios are often expressed in decibels.
Complete answer:
Let the initial reading on the decibel scale be M. Hence the corresponding intensity i.e. (${{I}_{1}}$) for that is given by,
$M=10\log \left( \dfrac{{{I}_{1}}}{{{I}_{0}}} \right)...(1)$ Now in the question it is given that the value of the scale increases by 1dB, hence the intensity(${{I}_{2}}$) corresponding to that is given by,
$M+1=10\log \left( \dfrac{{{I}_{2}}}{{{I}_{0}}} \right)...(2)$ . Now let us subtract equation 1 from 2
$\begin{align}
& \Rightarrow M+1-M=10\log \left( \dfrac{{{I}_{2}}}{{{I}_{0}}} \right)-10\log \left( \dfrac{{{I}_{1}}}{{{I}_{0}}} \right) \\
& \Rightarrow 1=10\log \left( \dfrac{\dfrac{{{I}_{2}}}{{{I}_{0}}}}{\dfrac{{{I}_{1}}}{{{I}_{0}}}} \right)=10\log \left( \dfrac{{{\text{I}}_{\text{2}}}}{{{\text{I}}_{\text{1}}}} \right) \\
& \Rightarrow \dfrac{1}{10}=\log \left( \dfrac{{{\text{I}}_{\text{2}}}}{{{\text{I}}_{\text{1}}}} \right) \\
& \Rightarrow 0.1=\log \left( \dfrac{{{\text{I}}_{\text{2}}}}{{{\text{I}}_{\text{1}}}} \right) \\
& \Rightarrow \dfrac{{{\text{I}}_{\text{2}}}}{{{\text{I}}_{\text{1}}}}={{10}^{0.1}}=1.26 \\
& \Rightarrow {{\text{I}}_{\text{2}}}=1.26{{\text{I}}_{\text{1}}} \\
\end{align}$
Hence the increase in the intensity is 26%.
Note:
The Decibel scale is used to the ratio of one power to another on a logarithmic scale, The logarithmic quantity being called the power level or field level, respectively. The definition of decibel is based on the measurement of power in telephony of the early 20th century in the bell system in the United states. This was basically named in honor of Alexander Graham Bell.. Today the decibel is used for a wide variety of measurements in science and engineering most prominently in acoustics, electronics etc. In electronics, the gains of amplifiers, attenuation of signals and signal to noise ratios are often expressed in decibels.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Difference Between Prokaryotic Cells and Eukaryotic Cells

Two of the body parts which do not appear in MRI are class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

