Answer

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**Hint:**Refer to the thermodynamic processes. If the process does not undergo change in pressure it is called an isobaric process if the same for the volume it is called isochoric process.

**Complete step by step answer:**

We need to verify every option to answer this question.

(A)At point O, the pressure and the volume become zero. The volume of the gas can never be zero. Therefore, the straight-line AB cannot pass through O.

(B)We know that, in an isobaric process, the pressure of the gas does not change. The straight-line AB represents an isochoric process. In an isobaric process, the temperature increases.We know that, in an isochoric process, the volume of the gas does not change. The straight-line BC represents an isochoric process. In an isochoric process, the temperature of the gas increases.

Therefore, the option (B) is incorrect.

(C)In an isochoric process, the volume of the gas does not change. The work done depends upon the change in the volume of the gas. Therefore, no work is done in the process represented by straight line BC.

Therefore, the option (C) is incorrect.

(D)The process represented by straight line CA is an isothermal process. In this process, internal energy of the system increases or decreases. Therefore, the heat supplied is not equal to the work done. Also, the volume of the gas increases if the work is done by the gas. But here the volume of the gas is decreasing.

Therefore, the option (D) is incorrect.

**So, the correct answer is “Option A”.**

**Note:**Check whether the straight line is starting from point A or from point C.

The starting point defines the initial volume of the gas.

At point O, the pressure and the volume become zero.

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