
Ammonium ion is:
(A) neither an acid or base
(B) both an acid and a base
(C) a conjugate acid
(D) a conjugate base
Answer
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Hint: Ammonium ion is formed when ammonia gets protonated (gain of ${{H}^{+}}$ion) when reacted with hydrochloric acid. Here ammonia is a weak base and hydrochloric acid is a strong acid. Gain and loss of proton by acid and base form conjugate acid –base pair.
Complete step by step solution:
As you know from your chemistry lessons that acid has the tendency to donate proton and base has the tendency to accept proton (Bronsted lowry concept).
-The absence and presence of protons in acid and base form conjugate acid-base pairs.
-Here, ammonia $\left( N{{H}_{3}} \right)$ a weak base gets protonated or accept a proton from hydrochloric acid $\left( HCl \right)$ which a strong acid to form ammonium ion.
\[N{{H}_{3}}\,+\,HCl\to \,NH_{4}^{+}\,+C{{l}^{-}}\]
\[N{{H}_{3}}\,+\,{{H}^{+}}C{{l}^{-}}\to \,NH_{4}^{+}\,+\,C{{l}^{-}}\]
-In this reaction ammonium ion behaves as a conjugate acid of $N{{H}_{3}}$and conjugate acids are formed when acid donates its proton basically ${{H}^{+}}$ to the base. Thus $C{{l}^{-}}$ is a conjugate base of $HCl$ .Conjugate bases are from when a proton is removed by an acid.
-From the reaction you have seen that ammonium ions have a positive charge on it this is due to the addition of one extra ${{H}^{+}}$in the ammonia.
-Ammonia is a weak base react with hydrochloric acid a strong acid to form ammonium ion which is a conjugate weak acid.
Thus, option (C) is the correct one.
Note: Do not confuse between the Arrhenius and Bronsted lowry concept. Conjugate acid-base pair theory was given by Bronsted lowry. Here, we usually talk about the gain and loss of protons and not about the electrons (Arrhenius concept).
Complete step by step solution:
As you know from your chemistry lessons that acid has the tendency to donate proton and base has the tendency to accept proton (Bronsted lowry concept).
-The absence and presence of protons in acid and base form conjugate acid-base pairs.
-Here, ammonia $\left( N{{H}_{3}} \right)$ a weak base gets protonated or accept a proton from hydrochloric acid $\left( HCl \right)$ which a strong acid to form ammonium ion.
\[N{{H}_{3}}\,+\,HCl\to \,NH_{4}^{+}\,+C{{l}^{-}}\]
\[N{{H}_{3}}\,+\,{{H}^{+}}C{{l}^{-}}\to \,NH_{4}^{+}\,+\,C{{l}^{-}}\]
-In this reaction ammonium ion behaves as a conjugate acid of $N{{H}_{3}}$and conjugate acids are formed when acid donates its proton basically ${{H}^{+}}$ to the base. Thus $C{{l}^{-}}$ is a conjugate base of $HCl$ .Conjugate bases are from when a proton is removed by an acid.
-From the reaction you have seen that ammonium ions have a positive charge on it this is due to the addition of one extra ${{H}^{+}}$in the ammonia.
-Ammonia is a weak base react with hydrochloric acid a strong acid to form ammonium ion which is a conjugate weak acid.
Thus, option (C) is the correct one.
Note: Do not confuse between the Arrhenius and Bronsted lowry concept. Conjugate acid-base pair theory was given by Bronsted lowry. Here, we usually talk about the gain and loss of protons and not about the electrons (Arrhenius concept).
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