
Ammonium chloride is a salt of:
A. Weak acid and weak base
B. Weak acid and strong base
C. Strong acid and strong base
D. Strong acid and weak base
Answer
585.6k+ views
Hint: In these types of questions, we first write the formula of the compound and then find out the anionic and cationic part of the compound, the anionic part comes from the acid and the cationic part comes from the base. Also, the ${{H}^{+}}$ ion comes from acid and $O{{H}^{-}}$ion comes from base.
Complete answer:
A neutralization reaction can be defined as a chemical reaction in which an acid and base quantitatively react together so as to form salt and water as products. In a neutralization reaction, there is also a combination of ${{H}^{+}}$ ions and $O{{H}^{-}}$ ions which form water.
Here, the formula of compound is $\text{N}{{\text{H}}_{4}}\text{Cl}$ thus the anionic part is ${{H}^{+}}$ and cationic part is. Ammonium chloride is a salt of strong acid which is hydrochloric acid and weak base which is ammonia.
The reaction is:
$\text{N}{{\text{H}}_{3}}\text{ }\!\!~\!\!\text{ }+\text{HCl }\!\!~\!\!\text{ }\to \text{ }\!\!~\!\!\text{ N}{{\text{H}}_{4}}\text{Cl }\!\!~\!\!\text{ }+{{\text{H}}_{2}}\text{O}$
Hence, the option (D) is the correct answer.
Note: Ammonium chloride is an inorganic compound with the formula \[N{{H}_{4}}Cl\] and a white crystalline salt that is highly soluble in water. Solutions of ammonium chloride are mildly acidic.
Complete answer:
A neutralization reaction can be defined as a chemical reaction in which an acid and base quantitatively react together so as to form salt and water as products. In a neutralization reaction, there is also a combination of ${{H}^{+}}$ ions and $O{{H}^{-}}$ ions which form water.
Here, the formula of compound is $\text{N}{{\text{H}}_{4}}\text{Cl}$ thus the anionic part is ${{H}^{+}}$ and cationic part is. Ammonium chloride is a salt of strong acid which is hydrochloric acid and weak base which is ammonia.
The reaction is:
$\text{N}{{\text{H}}_{3}}\text{ }\!\!~\!\!\text{ }+\text{HCl }\!\!~\!\!\text{ }\to \text{ }\!\!~\!\!\text{ N}{{\text{H}}_{4}}\text{Cl }\!\!~\!\!\text{ }+{{\text{H}}_{2}}\text{O}$
Hence, the option (D) is the correct answer.
Note: Ammonium chloride is an inorganic compound with the formula \[N{{H}_{4}}Cl\] and a white crystalline salt that is highly soluble in water. Solutions of ammonium chloride are mildly acidic.
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