
Akshit, Rajat, Sanjay and Nikunj each took the same spelling test.
Akshit spelled $\dfrac{7}{{10}}$ of the words correctly.
Rajat spelled $\dfrac{3}{4}$ of the words correctly.
Sanjay spelled $\dfrac{4}{5}$ of the words correctly.
Nikunj spelled $\dfrac{2}{3}$ of the words correctly.
Who spelled the least number of words correctly?
$
{\text{A}}{\text{. Akshit}} \\
{\text{B}}{\text{. Rajat}} \\
{\text{C}}{\text{. Sanjay}} \\
{\text{D}}{\text{. Nikunj}} \\
$
Answer
601.8k+ views
Hint: In order to find out who spelled the least number of words correctly, we arrange the fraction of words each person spelled in descending order. Whoever stands last has spelled the least number of words correctly.
Complete step-by-step answer:
Given Data,
Akshit - $\dfrac{7}{{10}}$ of total words
Rajat - $\dfrac{3}{4}$ of total words.
Sanjay - $\dfrac{4}{5}$ of total words.
Nikunj - $\dfrac{2}{3}$ of total words.
Now we compute each of the fractions into decimals to appropriately arrange them in descending order.
$
\Rightarrow \dfrac{7}{{10}} = 0.7 \\
\Rightarrow \dfrac{3}{4} = 0.75 \\
\Rightarrow \dfrac{4}{5} = 0.8 \\
\Rightarrow \dfrac{2}{3} = 0.67 \\
$
That means, akshit spelled 0.7 words correctly, rajat spelled 0.75 words correctly, sanjay spelled 0.8 words correctly and nikunj spelled 0.67 words correctly.
The descending order of people who spelled the most number of words correctly is –
0.8 > 0.75 > 0.7 > 0.67
⟹Sanjay > Rajat > Akshit > Nikunj
Therefore Nikunj spelled the least number of words correctly.
Option D is the correct answer.
Note: In order to solve this type of questions the key is to convert all the fractions given in the question into decimals so that we could easily compare them by looking at them.
The value of a fraction can be obtained by just dividing the numerator with the denominator.
Descending order is to arrange all the given elements from the biggest value to the smallest value in a decreasing order.
Ascending order is to arrange the elements in the increasing order, i.e. from smallest value to the biggest value.
Complete step-by-step answer:
Given Data,
Akshit - $\dfrac{7}{{10}}$ of total words
Rajat - $\dfrac{3}{4}$ of total words.
Sanjay - $\dfrac{4}{5}$ of total words.
Nikunj - $\dfrac{2}{3}$ of total words.
Now we compute each of the fractions into decimals to appropriately arrange them in descending order.
$
\Rightarrow \dfrac{7}{{10}} = 0.7 \\
\Rightarrow \dfrac{3}{4} = 0.75 \\
\Rightarrow \dfrac{4}{5} = 0.8 \\
\Rightarrow \dfrac{2}{3} = 0.67 \\
$
That means, akshit spelled 0.7 words correctly, rajat spelled 0.75 words correctly, sanjay spelled 0.8 words correctly and nikunj spelled 0.67 words correctly.
The descending order of people who spelled the most number of words correctly is –
0.8 > 0.75 > 0.7 > 0.67
⟹Sanjay > Rajat > Akshit > Nikunj
Therefore Nikunj spelled the least number of words correctly.
Option D is the correct answer.
Note: In order to solve this type of questions the key is to convert all the fractions given in the question into decimals so that we could easily compare them by looking at them.
The value of a fraction can be obtained by just dividing the numerator with the denominator.
Descending order is to arrange all the given elements from the biggest value to the smallest value in a decreasing order.
Ascending order is to arrange the elements in the increasing order, i.e. from smallest value to the biggest value.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

