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**Hint:**To answer this question, we first need to understand what speed and average speed is. The rate at which an object travels over a given distance is known as speed. The average speed of an object in a given time period is the object's distance travelled divided by the interval's length; the instantaneous speed is the average speed's limit as the interval's duration reaches nil.

**Complete step by step answer:**

As given in the question speed of the car when going to college = 20Km/h,

And speed of the car while returning back to home = 30Km/h.

Let the distance from Akhil’s home to college be x Km, so total distance travelled by Akhil is 2x Km.

Formula of speed$$

$$ Speed = $\dfrac{D}{T}$(where D is the distance travelled and T is the time taken)

Let the time taken by Akhil while going to college be ${t_1}$

Substituting the value in formula

$20\dfrac{{Km}}{h} = \dfrac{{xKm}}{{{t_1}}}$

Getting the value of ${t_1}$

${t_1} = \dfrac{x}{{20}}h$

Similarly, assuming the time taken by Akhil while coming back to home be ${t_2}$

Substituting the value in formula

$30\dfrac{{Km}}{h} = \dfrac{{xKm}}{{{t_2}}}$

Getting the value of ${t_2}$

${t_2} = \dfrac{x}{{30}}h$

Total time taken in complete trip = ${t_1} + {t_2}$

i.e. TT = $(\dfrac{x}{{20}} + \dfrac{x}{{30}})h$

Taking LCM

TT = $\dfrac{x}{{12}}h$

As discussed above total distance i.e. (TD) = 2xKm/h.

As we know that average speed = $\dfrac{{TD}}{{TT}}$ (where TT is the total time and TD is the total distance travelled)

Substituting values

Average speed = $\dfrac{{2x}}{{x/12}}$(total distance is 2x whereas total time is x/12)

So average speed = $2 \times 12 = 24Km/h$

So the final answer is 24Km/h.

**Note:**The total distance travelled divided by the time taken equals average speed, while average velocity equals displacement divided by time taken equals average velocity. The average speed is also a scalar quantity since speed is a scalar quantity, while velocity is a vector quantity.

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