
Akhil drove his car with a speed of 20km/h while going to his college when he returned to his home along the same route the speed of the car was 30km/h. Calculate the average speed of the car during the entire journey.
Answer
505.2k+ views
Hint: To answer this question, we first need to understand what speed and average speed is. The rate at which an object travels over a given distance is known as speed. The average speed of an object in a given time period is the object's distance travelled divided by the interval's length; the instantaneous speed is the average speed's limit as the interval's duration reaches nil.
Complete step by step answer:
As given in the question speed of the car when going to college = 20Km/h,
And speed of the car while returning back to home = 30Km/h.
Let the distance from Akhil’s home to college be x Km, so total distance travelled by Akhil is 2x Km.
Formula of speed$$
$$ Speed = $\dfrac{D}{T}$(where D is the distance travelled and T is the time taken)
Let the time taken by Akhil while going to college be ${t_1}$
Substituting the value in formula
$20\dfrac{{Km}}{h} = \dfrac{{xKm}}{{{t_1}}}$
Getting the value of ${t_1}$
${t_1} = \dfrac{x}{{20}}h$
Similarly, assuming the time taken by Akhil while coming back to home be ${t_2}$
Substituting the value in formula
$30\dfrac{{Km}}{h} = \dfrac{{xKm}}{{{t_2}}}$
Getting the value of ${t_2}$
${t_2} = \dfrac{x}{{30}}h$
Total time taken in complete trip = ${t_1} + {t_2}$
i.e. TT = $(\dfrac{x}{{20}} + \dfrac{x}{{30}})h$
Taking LCM
TT = $\dfrac{x}{{12}}h$
As discussed above total distance i.e. (TD) = 2xKm/h.
As we know that average speed = $\dfrac{{TD}}{{TT}}$ (where TT is the total time and TD is the total distance travelled)
Substituting values
Average speed = $\dfrac{{2x}}{{x/12}}$(total distance is 2x whereas total time is x/12)
So average speed = $2 \times 12 = 24Km/h$
So the final answer is 24Km/h.
Note: The total distance travelled divided by the time taken equals average speed, while average velocity equals displacement divided by time taken equals average velocity. The average speed is also a scalar quantity since speed is a scalar quantity, while velocity is a vector quantity.
Complete step by step answer:
As given in the question speed of the car when going to college = 20Km/h,
And speed of the car while returning back to home = 30Km/h.
Let the distance from Akhil’s home to college be x Km, so total distance travelled by Akhil is 2x Km.
Formula of speed$$
$$ Speed = $\dfrac{D}{T}$(where D is the distance travelled and T is the time taken)
Let the time taken by Akhil while going to college be ${t_1}$
Substituting the value in formula
$20\dfrac{{Km}}{h} = \dfrac{{xKm}}{{{t_1}}}$
Getting the value of ${t_1}$
${t_1} = \dfrac{x}{{20}}h$
Similarly, assuming the time taken by Akhil while coming back to home be ${t_2}$
Substituting the value in formula
$30\dfrac{{Km}}{h} = \dfrac{{xKm}}{{{t_2}}}$
Getting the value of ${t_2}$
${t_2} = \dfrac{x}{{30}}h$
Total time taken in complete trip = ${t_1} + {t_2}$
i.e. TT = $(\dfrac{x}{{20}} + \dfrac{x}{{30}})h$
Taking LCM
TT = $\dfrac{x}{{12}}h$
As discussed above total distance i.e. (TD) = 2xKm/h.
As we know that average speed = $\dfrac{{TD}}{{TT}}$ (where TT is the total time and TD is the total distance travelled)
Substituting values
Average speed = $\dfrac{{2x}}{{x/12}}$(total distance is 2x whereas total time is x/12)
So average speed = $2 \times 12 = 24Km/h$
So the final answer is 24Km/h.
Note: The total distance travelled divided by the time taken equals average speed, while average velocity equals displacement divided by time taken equals average velocity. The average speed is also a scalar quantity since speed is a scalar quantity, while velocity is a vector quantity.
Recently Updated Pages
What is lattice enthalpy How do you calculate the lattice class 11 chemistry CBSE

what is the free energy change left Delta G right when class 11 chemistry CBSE

List three events in the process of photosynthesis class 11 biology CBSE

Give a brief account on the canal system in sponge class 11 biology CBSE

Why do mountaineers carry oxygen cylinders while going class 11 social science CBSE

Which group of organisms are not constituents of a class 11 biology CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

