Answer
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Hint: In the given question, we have been given two time periods. Then the question asks us to add them. They can be simply added, but only one thing is to be kept in mind – if the sum of the months exceeds \[11\], i.e., \[12\] or more, we reduce their sum by \[12\] and add one to the sum of the years. The sum of the years has no such condition.
Complete step-by-step answer:
The given time durations to be added are \[20\,{\rm{ years\, }}6\,{\rm{ months}}\] and \[{\rm{16\, years\, 9\, months}}\].
First, we are going to add the years, \[Y = 20 + 16 = 36\].
Now, we are going to add the months, \[M = 6 + 9 = 15\]
Now, \[15\] is greater than \[11\], so we are going to subtract \[12\] from \[15\] and add \[1\] to the years.
So, \[M = 15 - 12 = 3\] and \[Y = 36 + 1 = 37\]
Hence, the sum of the two time durations is \[37\,{\rm{ years \,}}3\,{\rm{ months}}\].
Note: For solving these types of questions we should know the relation between year and month. We have to remember 12 months is equal to 1 year.
Complete step-by-step answer:
The given time durations to be added are \[20\,{\rm{ years\, }}6\,{\rm{ months}}\] and \[{\rm{16\, years\, 9\, months}}\].
First, we are going to add the years, \[Y = 20 + 16 = 36\].
Now, we are going to add the months, \[M = 6 + 9 = 15\]
Now, \[15\] is greater than \[11\], so we are going to subtract \[12\] from \[15\] and add \[1\] to the years.
So, \[M = 15 - 12 = 3\] and \[Y = 36 + 1 = 37\]
Hence, the sum of the two time durations is \[37\,{\rm{ years \,}}3\,{\rm{ months}}\].
Note: For solving these types of questions we should know the relation between year and month. We have to remember 12 months is equal to 1 year.
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