Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

Add \[395.6\] to \[48.07\] and subtract it from the sum of \[510.05\] and \[115.15\].

Answer
VerifiedVerified
579.3k+ views
Hint: At first, we have to add \[395.6\] to \[48.07\] and subtract from the sum of \[510.05\] to \[115.15\]. Then we have to subtract these two summations. That is we have to subtract the sum value of the first set of numbers from the sum of the second set of numbers.

Complete step-by-step answer:
It is given that; we have to add \[395.6\] to \[48.07\] and subtract from the sum of \[510.05\] to \[115.15\]. Then we have to subtract these two sums.
Now, let us add the first set of numbers.
That is let us add \[395.6\] to \[48.07\] we get,
\[395.6 + 48.07\]
On adding both the numbers we get, the sum as \[443.67\].
Now let us add the second set of numbers.
That is let us add \[510.05\] and \[115.15\], we get,
\[510.05 + 115.15\]
On adding both the numbers we get, the sum as \[625.2\]
Now we have to subtract, \[443.67\] from \[625.2\]
That is, \[625.2 - 443.67\] is what we have to find.
On subtracting both the numbers we get, \[181.53\]
Hence, we have found the final answer after subtraction is \[181.53\].
That is the subtraction of the sum of first set from the sum of second set of numbers is \[181.53\]
Hence \[(510.05 + 115.15) - (395.6 + 48.07) = 181.53\].

Additional information:
In mathematics addition, subtraction, multiplication and division are the basic algebraic operations.
While applying these four operations it follows a rule called BODMAS rule. Which is expanded as “Bracket of Division Multiplication Addition Subtraction”
That states that the operations that are mentioned in the bracket should be completed first and follows the order of division multiplication addition and finally the subtraction.

Note: A decimal is defined as a number expressed in decimal notation and generally applied to values that have a fractional part and separated from the integer side.

WhatsApp Banner