
Add $20 \text{hr}$ $34 \text{min}$ $ 8 \text{sec}$ and $8 \text{hr}$ $48 \text{min}$ $35 \text{sec}$.
Answer
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Hint: We simply add the given times. If the minute part is greater than \[60\min \], we will divide that by \[60\] and change it into hour and min. Then we will add that hour and minute with the answer and we will get our final answer.
Complete step-by-step answer:
It is given $20 \text{hr}$ $34 \text{min}$ $ 8 \text{sec}$ and $8 \text{hr}$ $48 \text{min}$ $35 \text{sec}$.
We have to find the sum of the above timings.
That is to add both of them,
$20 \text{hr}$ $34 \text{min}$ $ 8 \text{sec}$ + $8 \text{hr}$ $48 \text{min}$ $35 \text{sec}$.
We should add hours with hours, minutes with minutes and seconds with seconds.
Now by addition of hours in both the terms we get, 20 hours + 8 hours = 28 hours.
Next by addition of minutes in both the terms we get, 34 minutes + 48 minutes = 82 minutes.
Next by addition of seconds in both the terms we get, 8 seconds + 35 seconds = 43 seconds.
Hence we get, $28 \text{hr}$ $82 \text{min}$ $ 43 \text{sec}$
We know that, \[1h\] = $60 \text{min}$ but here the minute is more than $60 \text{min}$. So, we will change it into hours
So we convert $82 \text{min}$ into hours,
Now $82 \text{min}$ can be written as $82 \text{min}$ = $60 \text{min}$ + $22 \text{min}$
Then we can write the above equation as,
$82 \text{min}$ = $1 \text{hr}$ $22 \text{min}$
Now we will add $1 \text{hr}$ $22 \text{min}$ with $28 \text{hr}$ $43 \text{sec}$
By addition of it we get,
$29 \text{hr}$ $22 \text{min}$ $ 43 \text{sec}$
So, the final answer will be $29 \text{hr}$ $22 \text{min}$ $ 43 \text{sec}$
Hence, the sum of $20 \text{hr}$ $34 \text{min}$ $ 8 \text{sec}$ and $8 \text{hr}$ $48 \text{min}$ $35 \text{sec}$. is $29 \text{hr}$ $22 \text{min}$ $ 43 \text{sec}$
Note: We know that 1 minute = 60 seconds. Here in the final answer the number of seconds is 43 which is less than 60 seconds hence we will not change it suppose if the seconds in the final answer is greater than 60 we will convert it into minutes and add it to the final answer.
Complete step-by-step answer:
It is given $20 \text{hr}$ $34 \text{min}$ $ 8 \text{sec}$ and $8 \text{hr}$ $48 \text{min}$ $35 \text{sec}$.
We have to find the sum of the above timings.
That is to add both of them,
$20 \text{hr}$ $34 \text{min}$ $ 8 \text{sec}$ + $8 \text{hr}$ $48 \text{min}$ $35 \text{sec}$.
We should add hours with hours, minutes with minutes and seconds with seconds.
Now by addition of hours in both the terms we get, 20 hours + 8 hours = 28 hours.
Next by addition of minutes in both the terms we get, 34 minutes + 48 minutes = 82 minutes.
Next by addition of seconds in both the terms we get, 8 seconds + 35 seconds = 43 seconds.
Hence we get, $28 \text{hr}$ $82 \text{min}$ $ 43 \text{sec}$
We know that, \[1h\] = $60 \text{min}$ but here the minute is more than $60 \text{min}$. So, we will change it into hours
So we convert $82 \text{min}$ into hours,
Now $82 \text{min}$ can be written as $82 \text{min}$ = $60 \text{min}$ + $22 \text{min}$
Then we can write the above equation as,
$82 \text{min}$ = $1 \text{hr}$ $22 \text{min}$
Now we will add $1 \text{hr}$ $22 \text{min}$ with $28 \text{hr}$ $43 \text{sec}$
By addition of it we get,
$29 \text{hr}$ $22 \text{min}$ $ 43 \text{sec}$
So, the final answer will be $29 \text{hr}$ $22 \text{min}$ $ 43 \text{sec}$
Hence, the sum of $20 \text{hr}$ $34 \text{min}$ $ 8 \text{sec}$ and $8 \text{hr}$ $48 \text{min}$ $35 \text{sec}$. is $29 \text{hr}$ $22 \text{min}$ $ 43 \text{sec}$
Note: We know that 1 minute = 60 seconds. Here in the final answer the number of seconds is 43 which is less than 60 seconds hence we will not change it suppose if the seconds in the final answer is greater than 60 we will convert it into minutes and add it to the final answer.
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