Question

# A vessel has 4 liters and 500 ml of curd. In how many glasses, each of 25 ml of capacity, can it be filled?

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Hint: In the question the volume of curd in the vessel is 4 liters and 500 ml. Now we have to fill the curd into glasses of 25ml capacity. So, here we use the formula to calculate the number of glasses required= $\dfrac{Total\text{ }volume\text{ }of\text{ }curd}{capacity\text{ }of\text{ }glass}$

Complete step-by-step solution:
In this question the total volume of curd in the vessel is 4 liters and 500 ml.
Now, we will convert the total volume of curd into ml.
As we know that 1 liter=1000 ml
So, 4 liters= $4\times 1000$ ml
Total volume of curd in the vessel in milliliters=4000 ml+500 ml
Therefore, total volume of curd in the vessel=4500 ml.
We know that according to the question capacity of each glass=25 ml.
So, the number of glasses of capacity 25 ml required are= $\dfrac{Total\text{ }volume\text{ }of\text{ }curd}{capacity\text{ }of\text{ }glass}\cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \left( 1 \right)$
Be sure that both numerator (i.e. total volume of curd) and denominator (i.e. capacity of glass) are in the same physical units.
Here the total volume of curd is converted to ml as the capacity of each glass is in ml. So, there is no problem here as there are the same units in both numerator and denominator.
Now, we substitute the values of total volume of curd=4500 ml and capacity of glass=25 ml in equation (1)
So, the number of glasses of capacity 25 ml required $=\dfrac{4500}{25}\cdot \cdot \cdot \cdot \cdot \cdot \cdot \left( 2 \right)$
Now after the simplification of above equation 2, we will get the number of required glasses.
The number of glasses of capacity 25 ml required $=180$
Note: During solving these types of problems, sometimes using unit as ml gives better results than using unit as l as it avoids decimal and complexity. It is important that units should be similar in both
numerator and denominator. If not similar, convert either numerator or denominator to the same units as the other.