Question

A tile is 15cm long and 10cm wide the four walls of the kitchen to be tiled. If the length and breadth of each wall are 440cm and 750cm, how many tiles are required to tile the entire kitchen?

Answer 1

Hint:
Here, in the question we have given the length and width of tiles and the dimensions of the wall on which the tiles to be fitted. We have to calculate the no. of tiles required for the walls. So firstly, we have to calculate the area of tiles and then the area of the walls then we divide the area of walls by the area of the tiles.
Formula used: $Area = l \times b$

Complete step by step solution:
Here, first we will find the area of tiles
$ \Rightarrow Area = l \times b$
 $
   = 15cm \times 10cm \\
   = 150c{m^2} \\
 $
Area of tiles $ = 150c{m^2}$
Now, area of one wall
 $
   = l \times b \\
   = 440cm \times 750cm \\
   = 330000c{m^2} \\
 $
Here, in the kitchen there are four walls
Now, area of four walls
 $
   = 4 \times 330000 \\
   = 1320000c{m^2} \\
 $
Now if the area of one tile is equal to the \[150c{m^2}\]
the area of four walls is equal to the $ = 1320000c{m^2}$
Therefore, we will divide the area of four walls by the area of one tiles,
In this way we will find the no. of the tiles required.
Here, \[150c{m^2} \to 1\] tiles
 $
   = \dfrac{{1320000 \times 1}}{{150}} \\
   = \dfrac{{1320000}}{{150}} \\
   = 8800 \\
 $

Therefore, the 8800 tiles will be required for the entire Kitchen.

Note:
If the units of the given information are not the same then you have to convert them into any one of the given units. Here for the tiles and walls we have dimensions of the rectangle so we have used the formula of area of rectangle and the tiles are always fitted on the surface so we have used the concept of area.