
A student measured the diameter of a small steel ball using a screw gauge of least count $0.001 \mathrm{cm} .$ The main scale reading is $5 \mathrm{mm}$ and zero of circular scale division coincides with $25 divisions$ above the reference level. If the screw gauge has a zero error of $-0.004 \mathrm{cm},$ the correct diameter of the ball is?
(A) $0.053 \mathrm{cm}$
(B) $0.521\text{cm}$
(C) $0.529\text{cm}$
(D) $0.525\text{cm}$
Answer
589.5k+ views
Hint
The screw gauge is defined to be an instrument that is used for measuring exactly the diameter of a thin wire or the width of a sheet of a metal. It comprises a U-shaped mount which is fixed with a screwed pin which is fixed to a thimble. The least count of a screw gauge is $0.01mm$. Based on this concept we have to find the answer to this question.
Complete step by step answer
The Least count of the screw gauge is $=0.001 \mathrm{cm}$
The main scale reading of the screw gauge is $\mathrm{R}=5 \mathrm{mm}$ and $25 divisions$ above the reference level.
Zero error in the screw gauge $=-0.004 \mathrm{cm}$
Observed reading of the screw gauge$=0.5+25 \times 0.001$
$=0.5+0.025$
$=0.525\text{cm}$
Actual reading $=0.525+0.004$
$=0.529 \mathrm{cm}$
Therefore, the correct answer is Option (C).
Note
We should know the smallest value that can be measured by the measuring instrument is known as the least count of that instrument. We should also know that the least count error is defined as the error that is associated with the revolution of the instrument.
The screw gauge is defined to be an instrument that is used for measuring exactly the diameter of a thin wire or the width of a sheet of a metal. It comprises a U-shaped mount which is fixed with a screwed pin which is fixed to a thimble. The least count of a screw gauge is $0.01mm$. Based on this concept we have to find the answer to this question.
Complete step by step answer
The Least count of the screw gauge is $=0.001 \mathrm{cm}$
The main scale reading of the screw gauge is $\mathrm{R}=5 \mathrm{mm}$ and $25 divisions$ above the reference level.
Zero error in the screw gauge $=-0.004 \mathrm{cm}$
Observed reading of the screw gauge$=0.5+25 \times 0.001$
$=0.5+0.025$
$=0.525\text{cm}$
Actual reading $=0.525+0.004$
$=0.529 \mathrm{cm}$
Therefore, the correct answer is Option (C).
Note
We should know the smallest value that can be measured by the measuring instrument is known as the least count of that instrument. We should also know that the least count error is defined as the error that is associated with the revolution of the instrument.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

The largest wind power cluster is located in the state class 11 social science CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

What steps did the French revolutionaries take to create class 11 social science CBSE

Which among the following are examples of coming together class 11 social science CBSE

