Answer
Verified
396.3k+ views
Hint:
In our question we see that a solid sphere is given which is melted and recast into a small spherical ball , here we ignore the loss of material due to vaporization and consider that 100% material is melted and converted into a small spherical ball . Also we assume that here the density of the during melting and conversion volume always remain constant.
Complete step by step solution:
Let’s start the solution firstly we calculate the volume of a large sphere so that we get the idea of how much material will be going to melt.
Step 1- Volume of initial sphere is
\[
\dfrac{4}{3}\pi {r^3} \\
= \dfrac{4}{3}\pi {6^3}\,\,{m^3} \\
= 288\pi \,\,{m^3} \\
\]
Now we have the volume of larger sphere \[288\pi \,\,{m^3}\]
Next we have tried to find the volume of the smaller sphere, we already mention the formula of volume of sphere. Now you familiar with the formula, let’s use it here we have radius of small sphere as 0.6m
Step 2- Volume of smaller sphere
\[
= \dfrac{4}{3}\pi \,\,{0.6^3}\,\,{m^3} \\
= \dfrac{{36}}{{125}}\pi \,\,{m^3} \\
\]
Now we have the volume of the smaller sphere is \[\dfrac{{36}}{{125}}\pi \,\,{m^3}\]
Next we move towards the number of balls produced by using the below formula for the number of balls.
Step 3- Number of balls obtained
\[
= \dfrac{{total\;volume\;of\;initial\;sphere}}{{volume\;of\;smaller\;sphere}} \\
= \dfrac{{288\pi }}{{\dfrac{{36}}{{125}}\pi }} \\
= 125 \times 8 = 1000 \\
\]
Hence the new number of smaller balls is 1000.
Note:
Always don’t confuse melting the volume of the sphere as constant. If nothing is mentioned about matter loss we consider that volume remains constant. Sometimes these types of question losses are also mentioned in that case you will first subtract and then proceed further.
In our question we see that a solid sphere is given which is melted and recast into a small spherical ball , here we ignore the loss of material due to vaporization and consider that 100% material is melted and converted into a small spherical ball . Also we assume that here the density of the during melting and conversion volume always remain constant.
Complete step by step solution:
Let’s start the solution firstly we calculate the volume of a large sphere so that we get the idea of how much material will be going to melt.
Step 1- Volume of initial sphere is
\[
\dfrac{4}{3}\pi {r^3} \\
= \dfrac{4}{3}\pi {6^3}\,\,{m^3} \\
= 288\pi \,\,{m^3} \\
\]
Now we have the volume of larger sphere \[288\pi \,\,{m^3}\]
Next we have tried to find the volume of the smaller sphere, we already mention the formula of volume of sphere. Now you familiar with the formula, let’s use it here we have radius of small sphere as 0.6m
Step 2- Volume of smaller sphere
\[
= \dfrac{4}{3}\pi \,\,{0.6^3}\,\,{m^3} \\
= \dfrac{{36}}{{125}}\pi \,\,{m^3} \\
\]
Now we have the volume of the smaller sphere is \[\dfrac{{36}}{{125}}\pi \,\,{m^3}\]
Next we move towards the number of balls produced by using the below formula for the number of balls.
Step 3- Number of balls obtained
\[
= \dfrac{{total\;volume\;of\;initial\;sphere}}{{volume\;of\;smaller\;sphere}} \\
= \dfrac{{288\pi }}{{\dfrac{{36}}{{125}}\pi }} \\
= 125 \times 8 = 1000 \\
\]
Hence the new number of smaller balls is 1000.
Note:
Always don’t confuse melting the volume of the sphere as constant. If nothing is mentioned about matter loss we consider that volume remains constant. Sometimes these types of question losses are also mentioned in that case you will first subtract and then proceed further.
Recently Updated Pages
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Define absolute refractive index of a medium
Find out what do the algal bloom and redtides sign class 10 biology CBSE
Prove that the function fleft x right xn is continuous class 12 maths CBSE
Find the values of other five trigonometric functions class 10 maths CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Two charges are placed at a certain distance apart class 12 physics CBSE
Difference Between Plant Cell and Animal Cell
What organs are located on the left side of your body class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The planet nearest to earth is A Mercury B Venus C class 6 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
What is BLO What is the full form of BLO class 8 social science CBSE