
A serial book was published at \[{{7}^{th}}\] year intervals. When the \[{{7}^{th}}\] book was published the total sum of publication year was 13524. First book was published in
(a) 1911
(b) 1910
(c) 2002
(d) 1932
Answer
585.9k+ views
Hint: Consider ‘x’ as the year in which \[{{1}^{st}}\] book was published. Add 7 to each year to get the publishing year. The sum of all 7 published gives the publication of 13524. Hence solve the equation formed and get the value of x.
Complete step by step solution:
It is said that a serial book was published at an interval of 7 years. Now let us assume that the first book was published in year ‘x’. Books are published at an interval of 7 years.
\[{{1}^{st}}\] book was published in year = x
\[{{2}^{nd}}\] book was published in year = x + 7
\[{{3}^{rd}}\] book was published in year = x + 14
\[{{4}^{th}}\] book was published in year = x + 21
\[{{5}^{th}}\] book was published in year = x + 28
\[{{6}^{th}}\] book was published in year = x + 35
\[{{7}^{th}}\] book was published in year = x + 42
When the \[{{7}^{th}}\] book was issued, the sum of the publication year was 13, 524.
\[\therefore \] The sum of the publications of all 7 books = 13524.
\[\begin{align}
& x+\left( x+7 \right)+\left( x+14 \right)+\left( x+21 \right)+\left( x+28 \right)+\left( x+35 \right)+\left( x+42 \right)=13524 \\
& \therefore 7x+147=13524 \\
\end{align}\]
Let us simplify the above and find the value of x.
\[\begin{align}
& \therefore 7x=13524-147 \\
& 7x=13377 \\
& \therefore x=\dfrac{13377}{7}=1911 \\
\end{align}\]
Hence the first book was published in the year 1911.
\[\therefore \] Option (a) is the correct answer.
Note: The question might be a little confusing when you read at first. Total publications is the total number of books or printed copies of the serial published. The number of printed copies of the 7 books is 13524. Thus solve the problem by keeping these points in mind. One might think that the answer should be a multiple of 7 and using this concept, they can eliminate the options. But doing this will not ease things because all options except (b) are divisible by 7. This method should not be adopted and the traditional method must be followed.
Complete step by step solution:
It is said that a serial book was published at an interval of 7 years. Now let us assume that the first book was published in year ‘x’. Books are published at an interval of 7 years.
\[{{1}^{st}}\] book was published in year = x
\[{{2}^{nd}}\] book was published in year = x + 7
\[{{3}^{rd}}\] book was published in year = x + 14
\[{{4}^{th}}\] book was published in year = x + 21
\[{{5}^{th}}\] book was published in year = x + 28
\[{{6}^{th}}\] book was published in year = x + 35
\[{{7}^{th}}\] book was published in year = x + 42
When the \[{{7}^{th}}\] book was issued, the sum of the publication year was 13, 524.
\[\therefore \] The sum of the publications of all 7 books = 13524.
\[\begin{align}
& x+\left( x+7 \right)+\left( x+14 \right)+\left( x+21 \right)+\left( x+28 \right)+\left( x+35 \right)+\left( x+42 \right)=13524 \\
& \therefore 7x+147=13524 \\
\end{align}\]
Let us simplify the above and find the value of x.
\[\begin{align}
& \therefore 7x=13524-147 \\
& 7x=13377 \\
& \therefore x=\dfrac{13377}{7}=1911 \\
\end{align}\]
Hence the first book was published in the year 1911.
\[\therefore \] Option (a) is the correct answer.
Note: The question might be a little confusing when you read at first. Total publications is the total number of books or printed copies of the serial published. The number of printed copies of the 7 books is 13524. Thus solve the problem by keeping these points in mind. One might think that the answer should be a multiple of 7 and using this concept, they can eliminate the options. But doing this will not ease things because all options except (b) are divisible by 7. This method should not be adopted and the traditional method must be followed.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

