
A school team won 6 games this year against 4 games won last year what is the percent increase?
Answer
584.4k+ views
Hint: Cent means hundred and percent simply means a part per hundred, it is a way of expressing amount per hundred. It is denoted by the symbol ‘%’. It is a dimensionless quantity.
For example, 30 % of ‘x’ means \[\dfrac{{30}}{{100}}x\]
That means what will be the \[\dfrac{{30}}{{100}}th\] part of the x.
Percentage formula = \[\dfrac{{value}}{{totalvalue}} \times 100\]
Example, if a student gets 15 marks out of 20 then,
Percentage of the marks \[\dfrac{{15}}{{20}} \times 100 = 75\% \]
Percentage is used for making comparison and amount of change in any value.
Percent increase or decrease is given by the formula,
\[ = \dfrac{{Change{\text{ }}in{\text{ }}the{\text{ }}value}}{{Initial{\text{ }}value}} \times 100\]
Complete step-by-step answer:
Given, Number of games won in current year = 6
Number of games won last year = 4
That is, the initial value = 4
So the difference in the games = 2
Thus the percent increase in the number of games \[ = \dfrac{{difference{\text{ }}in{\text{ }}the{\text{ }}games}}{{Base/initial\;value}}\]
\[ = \dfrac{2}{4} \times 100\]\[ = 50\% \]
Note: While finding the change in percentage we always take the base value that is the initial value we never take the final value.
Also x% of y = y% of x
For example, 30 % of ‘x’ means \[\dfrac{{30}}{{100}}x\]
That means what will be the \[\dfrac{{30}}{{100}}th\] part of the x.
Percentage formula = \[\dfrac{{value}}{{totalvalue}} \times 100\]
Example, if a student gets 15 marks out of 20 then,
Percentage of the marks \[\dfrac{{15}}{{20}} \times 100 = 75\% \]
Percentage is used for making comparison and amount of change in any value.
Percent increase or decrease is given by the formula,
\[ = \dfrac{{Change{\text{ }}in{\text{ }}the{\text{ }}value}}{{Initial{\text{ }}value}} \times 100\]
Complete step-by-step answer:
Given, Number of games won in current year = 6
Number of games won last year = 4
That is, the initial value = 4
So the difference in the games = 2
Thus the percent increase in the number of games \[ = \dfrac{{difference{\text{ }}in{\text{ }}the{\text{ }}games}}{{Base/initial\;value}}\]
\[ = \dfrac{2}{4} \times 100\]\[ = 50\% \]
Note: While finding the change in percentage we always take the base value that is the initial value we never take the final value.
Also x% of y = y% of x
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