
A rhombus shaped field has green grass for 18 cows to graze. If each side of the rhombus is 30 m and its longer diagonal is 48 m (as shown in the figure below the question) , how much area of the grass field will each cow be getting?
Answer
515.6k+ views
Hint: In above question first of all we will find the second diagonal of the rhombus field using Pythagoras theorem and and we will use the formula of area of rhombus to calculate its area then by using unitary method we will calculate the area of the grass each cow getting. Also we will use the formula of area of rhombus which is given below,
\[area=\dfrac{1}{2}\times {{d}_{1}}\times {{d}_{2}}\] where d1 and d2 are diagonal of the rhombus.
Complete step-by-step answer:
As we know the Pythagoras theorem is that the sum of squares of hypotenuse is equal to the sum of the square of its perpendicular and its base in a right angle triangle.
So, in $\vartriangle AOC$ as shown in the figure we have ,
\[\begin{align}
& O{{A}^{2}}={{30}^{2}}-{{24}^{2}} \\
& \Rightarrow OA=\sqrt{900-576} \\
& \Rightarrow OA=\sqrt{324}=18m \\
\end{align}\]
Now, the second diagonal is equal to twice OA= 36m.
For the rhombus we have two diagonal 48m and 36m,
\[area=\dfrac{1}{2}\times 48\times 36=864{{m}^{2}}\]
So, we have the above area of green grass for the 18 cows.
For the 1 cow the area = \[\dfrac{864}{18}=48{{m}^{2}}\]
Therefore, we get the area of grass field for each cow is equal to \[48{{m}^{2}}.\]
NOTE: Just remember the formula for the area of rhombus and also be careful while doing calculation as there is a chance that we may make silly mistakes and we will get the incorrect answer. Make sure that all the lengths are in the same units while computing area.
\[area=\dfrac{1}{2}\times {{d}_{1}}\times {{d}_{2}}\] where d1 and d2 are diagonal of the rhombus.
Complete step-by-step answer:
As we know the Pythagoras theorem is that the sum of squares of hypotenuse is equal to the sum of the square of its perpendicular and its base in a right angle triangle.
So, in $\vartriangle AOC$ as shown in the figure we have ,
\[\begin{align}
& O{{A}^{2}}={{30}^{2}}-{{24}^{2}} \\
& \Rightarrow OA=\sqrt{900-576} \\
& \Rightarrow OA=\sqrt{324}=18m \\
\end{align}\]
Now, the second diagonal is equal to twice OA= 36m.
For the rhombus we have two diagonal 48m and 36m,
\[area=\dfrac{1}{2}\times 48\times 36=864{{m}^{2}}\]
So, we have the above area of green grass for the 18 cows.
For the 1 cow the area = \[\dfrac{864}{18}=48{{m}^{2}}\]
Therefore, we get the area of grass field for each cow is equal to \[48{{m}^{2}}.\]
NOTE: Just remember the formula for the area of rhombus and also be careful while doing calculation as there is a chance that we may make silly mistakes and we will get the incorrect answer. Make sure that all the lengths are in the same units while computing area.
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