
A rectangular sheet of paper 44 cm $\times $ 20 cm is rolled along its length to form a cylinder. Find the volume of the cylinder so formed.
Answer
512.4k+ views
Hint:Using the concept that the rectangular piece of paper is rolled along its length, the length of the piece of paper forms the circumference of the base of the cylinder and breadth of paper forms the height of the cylinder.Substituting these values in volume of cylinder formula we get required answer.
Complete step-by-step answer:
When the rectangular piece of paper is rolled along its length, the length of the piece of paper forms the circumference of the base of the cylinder and the breadth of paper forms the height of the cylinder.
Length of the rectangular piece of paper is 44 cm and width of the rectangular paper is 20 cm
Let us say that the circular discs are stacked up to the height. Now, the volume of the cylinder will be the product of the base area of the discs and the height.
The whole length of the circular base = circumference of the circular base = 44 cm.
The circumference of the circular base $=2\pi r$
$44=2\pi r$
Dividing both sides by 2, we get
$22=\pi r$
Put the value of the $\pi =\dfrac{22}{7}$ , we get
$22=\dfrac{22}{7}(r)$
Dividing both sides by 22, we get
$1=\dfrac{1}{7}(r)$
$7=r$
$r=7$
The area of the circular base $=\pi {{r}^{2}}$
The area of the circular base \[=\dfrac{22}{7}\times {{\left( 7 \right)}^{2}}=22\times 7=154\]
Height of the cylinder = width of the rectangular paper = 20 cm.
The volume of the cylinder = $154\times 20=3080$ .
Hence the volume of the cylinder is 3080 $c{{m}^{3}}$.
Note: Alternatively, you could substitute the radius and height of the cylinder directly into the formula for volume of the cylinder $\left( V=\pi {{r}^{2}}h \right)$ we get the same answer.
Complete step-by-step answer:
When the rectangular piece of paper is rolled along its length, the length of the piece of paper forms the circumference of the base of the cylinder and the breadth of paper forms the height of the cylinder.
Length of the rectangular piece of paper is 44 cm and width of the rectangular paper is 20 cm
Let us say that the circular discs are stacked up to the height. Now, the volume of the cylinder will be the product of the base area of the discs and the height.
The whole length of the circular base = circumference of the circular base = 44 cm.
The circumference of the circular base $=2\pi r$
$44=2\pi r$
Dividing both sides by 2, we get
$22=\pi r$
Put the value of the $\pi =\dfrac{22}{7}$ , we get
$22=\dfrac{22}{7}(r)$
Dividing both sides by 22, we get
$1=\dfrac{1}{7}(r)$
$7=r$
$r=7$
The area of the circular base $=\pi {{r}^{2}}$
The area of the circular base \[=\dfrac{22}{7}\times {{\left( 7 \right)}^{2}}=22\times 7=154\]
Height of the cylinder = width of the rectangular paper = 20 cm.
The volume of the cylinder = $154\times 20=3080$ .
Hence the volume of the cylinder is 3080 $c{{m}^{3}}$.
Note: Alternatively, you could substitute the radius and height of the cylinder directly into the formula for volume of the cylinder $\left( V=\pi {{r}^{2}}h \right)$ we get the same answer.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Trending doubts
Is Cellular respiration an Oxidation or Reduction class 11 chemistry CBSE

In electron dot structure the valence shell electrons class 11 chemistry CBSE

What is the Pitti Island famous for ABird Sanctuary class 11 social science CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Number of valence electrons in Chlorine ion are a 16 class 11 chemistry CBSE

What is the modal class for the following table given class 11 maths CBSE
