
A pair of linear equations \[x + 2y - 4 = 0,\,2x + 4y - 12 = 0\] has \[\_\_\] solutions.
Answer
508.2k+ views
Hint: We are given a pair of linear equations. We have to find the number of solutions they have. We first check if they are parallel or not, and to do so we find the ratios of corresponding coefficients. If the ratios of the coefficients of the two variables are equal but different from the ratio of constants, we say that the pair of linear equations is parallel. We will use this condition here to solve this question.
Formula used: For pair of equations\[ax + by - c = 0,\,dx + ey - f = 0\], the condition of them to be parallel is,
\[\dfrac{a}{d} = \dfrac{b}{e} \ne \dfrac{c}{f}\]
Complete step-by-step solution:
We are given a pair of linear equations as,
\[x + 2y - 4 = 0,\,2x + 4y - 12 = 0\]
We have to find the number of solutions they have. To do so we first check if they are parallel or not. We do it by finding the ratios of coefficients of corresponding variables and also the ratio of constants. For pair of equations\[ax + by - c = 0,\,dx + ey - f = 0\], the condition of them to be parallel is,
\[\dfrac{a}{d} = \dfrac{b}{e} \ne \dfrac{c}{f}\]
Using this, we find the ratio for given pair as,
\[
\dfrac{1}{2} = \dfrac{2}{4} \ne \dfrac{{ - 4}}{{ - 12}} \\
\Rightarrow \dfrac{1}{2} = \dfrac{1}{2} \ne \dfrac{1}{3} \\
\]
Hence the condition of parallelism is satisfied. Thus the pair of linear equations is parallel.
Since, we know that pair of parallel linear equations has no solution, so we fill in the blank as
A pair of linear equations \[x + 2y - 4 = 0,\,2x + 4y - 12 = 0\] has a \[0\] solution.
Note: While trying to find the number of solutions to the pair of linear equations, we at first hand always see if they are parallel or perpendicular or not. Then we move ahead to other methods. Number solution means the number of times both the lines cut each in a Cartesian plane.
Formula used: For pair of equations\[ax + by - c = 0,\,dx + ey - f = 0\], the condition of them to be parallel is,
\[\dfrac{a}{d} = \dfrac{b}{e} \ne \dfrac{c}{f}\]
Complete step-by-step solution:
We are given a pair of linear equations as,
\[x + 2y - 4 = 0,\,2x + 4y - 12 = 0\]
We have to find the number of solutions they have. To do so we first check if they are parallel or not. We do it by finding the ratios of coefficients of corresponding variables and also the ratio of constants. For pair of equations\[ax + by - c = 0,\,dx + ey - f = 0\], the condition of them to be parallel is,
\[\dfrac{a}{d} = \dfrac{b}{e} \ne \dfrac{c}{f}\]
Using this, we find the ratio for given pair as,
\[
\dfrac{1}{2} = \dfrac{2}{4} \ne \dfrac{{ - 4}}{{ - 12}} \\
\Rightarrow \dfrac{1}{2} = \dfrac{1}{2} \ne \dfrac{1}{3} \\
\]
Hence the condition of parallelism is satisfied. Thus the pair of linear equations is parallel.
Since, we know that pair of parallel linear equations has no solution, so we fill in the blank as
A pair of linear equations \[x + 2y - 4 = 0,\,2x + 4y - 12 = 0\] has a \[0\] solution.
Note: While trying to find the number of solutions to the pair of linear equations, we at first hand always see if they are parallel or perpendicular or not. Then we move ahead to other methods. Number solution means the number of times both the lines cut each in a Cartesian plane.
Recently Updated Pages
Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

