
A mole is defined as:
A) Molecular weight expressed in grams.
B) Molecular weight divided by $1{\text{ g}}$ of ${{\text{H}}_{\text{2}}}$.
C) Number of particles contained in $12{\text{ g}}$ of ${\text{C}}$ of atomic mass 12.
D) Number of molecules contained in one litre of a gas at STP.
Answer
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Hint: To solve this we must know that mole is the unit of measurement used for measuring the amount of a substance in the International System of Units (SI). The unit of mole is mol. Mole is a standard scientific unit which is used for measuring large quantities of small entities like ions or atoms or molecules.
Complete solution:
We know that mole is the unit of measurement used for measuring the amount of a substance in the International System of Units (SI). The unit of mole is mol. mole is a standard scientific unit which is used for measuring large quantities of small entities like ions or atoms or molecules.
Mole is the ratio of mass of a substance in grams to the molar mass of the substance n grams per mol. Thus,
${\text{Number of moles}}\left( {{\text{mol}}} \right) = \dfrac{{{\text{Mass}}\left( {\text{g}} \right)}}{{{\text{Molar mass}}\left( {{\text{g/mol}}} \right)}}$
Thus, mole is not molecular weight expressed in grams. Thus, option (A) and option (B) are not correct.
$12{\text{ g}}$ of ${\text{C}}$ of atomic mass 12 contains one mole of carbon. $12{\text{ g}}$ of ${\text{C}}$ of atomic mass 12 contains $6.022 \times {10^{23}}$ carbon atoms. $6.022 \times {10^{23}}$ is Avogadro's number.
Also, one mole of any substance contains $6.022 \times {10^{23}}$ ions or atoms or molecules of the substance.
Thus, option (C) is correct.
Also, one mole of an ideal gas occupies a volume of $22.4{\text{ L}}$ at STP i.e. standard temperature and pressure.
Thus, option (D) is not correct.
Thus, mole can be defined as the number of particles contained in $12{\text{ g}}$ of ${\text{C}}$ of atomic mass 12.
Thus, the correct option is (C) number of particles contained in $12{\text{ g}}$ of ${\text{C}}$ of atomic mass 12.
Thus, the correct option is (C)
Note:The mole is defined as the Avogadro’s number which is equal to $6.022 \times {10^{23}}$. The number of entities like ions or atoms or molecules in one mole is the same for all the substances irrespective of the molecular weight or nature of the substance.
Complete solution:
We know that mole is the unit of measurement used for measuring the amount of a substance in the International System of Units (SI). The unit of mole is mol. mole is a standard scientific unit which is used for measuring large quantities of small entities like ions or atoms or molecules.
Mole is the ratio of mass of a substance in grams to the molar mass of the substance n grams per mol. Thus,
${\text{Number of moles}}\left( {{\text{mol}}} \right) = \dfrac{{{\text{Mass}}\left( {\text{g}} \right)}}{{{\text{Molar mass}}\left( {{\text{g/mol}}} \right)}}$
Thus, mole is not molecular weight expressed in grams. Thus, option (A) and option (B) are not correct.
$12{\text{ g}}$ of ${\text{C}}$ of atomic mass 12 contains one mole of carbon. $12{\text{ g}}$ of ${\text{C}}$ of atomic mass 12 contains $6.022 \times {10^{23}}$ carbon atoms. $6.022 \times {10^{23}}$ is Avogadro's number.
Also, one mole of any substance contains $6.022 \times {10^{23}}$ ions or atoms or molecules of the substance.
Thus, option (C) is correct.
Also, one mole of an ideal gas occupies a volume of $22.4{\text{ L}}$ at STP i.e. standard temperature and pressure.
Thus, option (D) is not correct.
Thus, mole can be defined as the number of particles contained in $12{\text{ g}}$ of ${\text{C}}$ of atomic mass 12.
Thus, the correct option is (C) number of particles contained in $12{\text{ g}}$ of ${\text{C}}$ of atomic mass 12.
Thus, the correct option is (C)
Note:The mole is defined as the Avogadro’s number which is equal to $6.022 \times {10^{23}}$. The number of entities like ions or atoms or molecules in one mole is the same for all the substances irrespective of the molecular weight or nature of the substance.
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