Question

A man sold an article at a loss of 20 percent. If he had sold it for Rs.12 more than he would have gained 10 percent. The cost price of the article is:-
A. Rs.60
B. Rs.40
C. Rs.30
D. Rs.22

Answer 1

Hint: In order to solve this problem you have to assume the variable as cost price then make equations according to the question given.

Complete step-by-step answer:

Let the cost price of the article be x.
We know that ${\text{a% }}\,{\text{of b}}\,{\text{can be written as = }}\dfrac{{a \times b}}{{100}}$
The man sold the article at 20% loss then he sold it in:
${\text{x - }}\dfrac{{{\text{20x}}}}{{100}} = .8{\text{x}}$
It is given that if he sold at Rs.12 more than he would have profit of 10%.
So the equation can be formulated as:
\[
  {\text{8x + 12 = x + }}\,\dfrac{{10{\text{x}}}}{{100}} \\
  12 = 1.1{\text{x - 0}}{\text{.8x}} \\
  {\text{0}}{\text{.3x = 12}} \\
  {\text{x = }}\dfrac{{120}}{3} = 40 \\
\]
So, the cost price of the item is 40.
The correct option is B.

Note: Whenever you face such type of problems you have to assume the variable of the term which you have to find out then make equations according to the conditions provided and get the value of the variable. Proceeding like this will solve your problem.