# A man deposits Rs.8,000 in a bank for 3 years at 5 % per annum compound interest. After 3 years he will get it.

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**Hint:**In this question principal amount is given , time is given , rate of interest is given . We have to find the amount after the time . We already know the formula for amount after time ‘t’.

A = $P{\left( {1 + \dfrac{R}{{100}}} \right)^t}$

Where ,

P = Principal amount

R = rate of interest

t = time

We have to substitute the value in the question in the formula mentioned and find the amount after 3 years. Let us try it !!!

**Complete step-by-step solution:**

In the the question given,

P = Principal amount = Rs.8,000

R = rate of interest = 5 % per annum

t = time = 3 years

Amount after 3 years A = $P{\left( {1 + \dfrac{R}{{100}}} \right)^t}$

$ = 8000{\left( {1 + \dfrac{5}{{100}}} \right)^3} \\

= 8000{\left( {\dfrac{{100 + 5}}{{100}}} \right)^3} \\

= 8000{\left( {\dfrac{{105}}{{100}}} \right)^3} \\

= 9261 $

**Hence money after 3 years for principal amount Rs.8000 , rate of interest is 5% per annum is Rs.9,261 .**

**Note:**The concept of interest is in use vastly nowadays . If the interest rates vary by different year by year. The total amount is given by

A=$P\left( {1 + \dfrac{{{r_1}}}{{100}}} \right)\left( {1 + \dfrac{{{r_2}}}{{100}}} \right)...........$ for shortcut methods . But the interest is calculated year by year for better understanding. There is another process for this problem. Alternatively , That method is to calculate interest year by year and summing up. The amount calculated in first year is taken as principal amount and second year so on .

Last updated date: 21st Sep 2023

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