
A magnesium ribbon is burnt in oxygen to give a white compound ‘X’ accompanied by emission of light. If the burning ribbon is now placed in an atmosphere of nitrogen, it continues to burn and forms a compound ‘Y’. Write a balanced chemical equation when ‘X’ is dissolved in water.
A. ${\text{2 Mg}}\,\,\,{\text{ + }}\,\,{{\text{O}}_2} \to \,2\,{\text{MgO}}$
B. ${\text{3 Mg}}\,\,\,{\text{ + }}\,\,{{\text{N}}_2} \to \,{\text{M}}{{\text{g}}_3}{{\text{N}}_2}$
C. ${\text{MgO}}\,\,\,{\text{ + }}\,\,{{\text{H}}_2}{\text{O}} \to \,{\text{Mg}}{\left( {{\text{OH}}} \right)_2}$
D. ${\text{Mg}}\,\,{\text{ + }}\,\,{{\text{H}}_2}{\text{O}} \to \,{\text{Mg}}{\left( {{\text{OH}}} \right)_2}$
Answer
509.1k+ views
Hint: On burning magnesium in oxygen, oxides are formed. Oxides on dissolving in water, hydroxides form. When alkaline earth metal burns in presence of oxygen, the oxides of alkaline earth metal forms.
Complete answer:
When burnt alkaline earth metals are placed in a nitrogen environment, the nitrides of alkaline earth metal forms.
When oxides of alkaline earth metal dissolve in water, the hydroxides of alkaline earth metal form.
When a magnesium ribbon is burnt in oxygen a white compound magnesium oxide ${\text{MgO}}$ is formed accompanied by the emission of light. So, compound ‘X’ is magnesium oxide.
If the burning magnesium ribbon is placed in a nitrogen atmosphere, the magnesium nitride ${\text{M}}{{\text{g}}_{\text{3}}}{{\text{N}}_{\text{2}}}$ forms. So, compound ‘Y’ is a magnesium nitride.
When the white compounds magnesium oxide ${\text{MgO}}$ is dissolved in water the magnesium hydroxide forms.
The reaction is represented as follows:
${\text{MgO}}\,\,\,{\text{ + }}\,\,{{\text{H}}_2}{\text{O}} \to \,{\text{Mg}}{\left( {{\text{OH}}} \right)_2}$
So, option (C) is correct.
Additional Information: Option (A) represents the reaction when magnesium ribbon is burnt in oxygen that is the formation of ‘X’ not the reaction of dissolution of ‘X’ so, option (A) is incorrect.
Option (B) represents the reaction when magnesium ribbon is burnt in nitrogen that is the formation of ‘Y’ not the reaction of dissolution of ‘X’ so option (B) is incorrect.
Option (D) represents the reaction on the dissolution of magnesium ribbon in water not the reaction of dissolution of ‘X’ so option (D) is incorrect.
Note: The alkaline earth metal forms ${\text{MO}}$ type oxide. Only the barium is an exception which forms peroxide. The alkaline earth metal forms ${{\text{M}}_3}{{\text{N}}_2}$ type nitrides. The alkaline earth metal forms ${\text{M}}{\left( {{\text{OH}}} \right)_2}$ type hydroxides.
Complete answer:
When burnt alkaline earth metals are placed in a nitrogen environment, the nitrides of alkaline earth metal forms.
When oxides of alkaline earth metal dissolve in water, the hydroxides of alkaline earth metal form.
When a magnesium ribbon is burnt in oxygen a white compound magnesium oxide ${\text{MgO}}$ is formed accompanied by the emission of light. So, compound ‘X’ is magnesium oxide.
If the burning magnesium ribbon is placed in a nitrogen atmosphere, the magnesium nitride ${\text{M}}{{\text{g}}_{\text{3}}}{{\text{N}}_{\text{2}}}$ forms. So, compound ‘Y’ is a magnesium nitride.
When the white compounds magnesium oxide ${\text{MgO}}$ is dissolved in water the magnesium hydroxide forms.
The reaction is represented as follows:
${\text{MgO}}\,\,\,{\text{ + }}\,\,{{\text{H}}_2}{\text{O}} \to \,{\text{Mg}}{\left( {{\text{OH}}} \right)_2}$
So, option (C) is correct.
Additional Information: Option (A) represents the reaction when magnesium ribbon is burnt in oxygen that is the formation of ‘X’ not the reaction of dissolution of ‘X’ so, option (A) is incorrect.
Option (B) represents the reaction when magnesium ribbon is burnt in nitrogen that is the formation of ‘Y’ not the reaction of dissolution of ‘X’ so option (B) is incorrect.
Option (D) represents the reaction on the dissolution of magnesium ribbon in water not the reaction of dissolution of ‘X’ so option (D) is incorrect.
Note: The alkaline earth metal forms ${\text{MO}}$ type oxide. Only the barium is an exception which forms peroxide. The alkaline earth metal forms ${{\text{M}}_3}{{\text{N}}_2}$ type nitrides. The alkaline earth metal forms ${\text{M}}{\left( {{\text{OH}}} \right)_2}$ type hydroxides.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What is the missing number in the sequence 259142027 class 10 maths CBSE

