A magnesium ribbon is burnt in oxygen to give a white compound ‘X’ accompanied by emission of light. If the burning ribbon is now placed in an atmosphere of nitrogen, it continues to burn and forms a compound ‘Y’. Write a balanced chemical equation when ‘X’ is dissolved in water.
A. ${\text{2 Mg}}\,\,\,{\text{ + }}\,\,{{\text{O}}_2} \to \,2\,{\text{MgO}}$
B. ${\text{3 Mg}}\,\,\,{\text{ + }}\,\,{{\text{N}}_2} \to \,{\text{M}}{{\text{g}}_3}{{\text{N}}_2}$
C. ${\text{MgO}}\,\,\,{\text{ + }}\,\,{{\text{H}}_2}{\text{O}} \to \,{\text{Mg}}{\left( {{\text{OH}}} \right)_2}$
D. ${\text{Mg}}\,\,{\text{ + }}\,\,{{\text{H}}_2}{\text{O}} \to \,{\text{Mg}}{\left( {{\text{OH}}} \right)_2}$
Answer
544.8k+ views
Hint: On burning magnesium in oxygen, oxides are formed. Oxides on dissolving in water, hydroxides form. When alkaline earth metal burns in presence of oxygen, the oxides of alkaline earth metal forms.
Complete answer:
When burnt alkaline earth metals are placed in a nitrogen environment, the nitrides of alkaline earth metal forms.
When oxides of alkaline earth metal dissolve in water, the hydroxides of alkaline earth metal form.
When a magnesium ribbon is burnt in oxygen a white compound magnesium oxide ${\text{MgO}}$ is formed accompanied by the emission of light. So, compound ‘X’ is magnesium oxide.
If the burning magnesium ribbon is placed in a nitrogen atmosphere, the magnesium nitride ${\text{M}}{{\text{g}}_{\text{3}}}{{\text{N}}_{\text{2}}}$ forms. So, compound ‘Y’ is a magnesium nitride.
When the white compounds magnesium oxide ${\text{MgO}}$ is dissolved in water the magnesium hydroxide forms.
The reaction is represented as follows:
${\text{MgO}}\,\,\,{\text{ + }}\,\,{{\text{H}}_2}{\text{O}} \to \,{\text{Mg}}{\left( {{\text{OH}}} \right)_2}$
So, option (C) is correct.
Additional Information: Option (A) represents the reaction when magnesium ribbon is burnt in oxygen that is the formation of ‘X’ not the reaction of dissolution of ‘X’ so, option (A) is incorrect.
Option (B) represents the reaction when magnesium ribbon is burnt in nitrogen that is the formation of ‘Y’ not the reaction of dissolution of ‘X’ so option (B) is incorrect.
Option (D) represents the reaction on the dissolution of magnesium ribbon in water not the reaction of dissolution of ‘X’ so option (D) is incorrect.
Note: The alkaline earth metal forms ${\text{MO}}$ type oxide. Only the barium is an exception which forms peroxide. The alkaline earth metal forms ${{\text{M}}_3}{{\text{N}}_2}$ type nitrides. The alkaline earth metal forms ${\text{M}}{\left( {{\text{OH}}} \right)_2}$ type hydroxides.
Complete answer:
When burnt alkaline earth metals are placed in a nitrogen environment, the nitrides of alkaline earth metal forms.
When oxides of alkaline earth metal dissolve in water, the hydroxides of alkaline earth metal form.
When a magnesium ribbon is burnt in oxygen a white compound magnesium oxide ${\text{MgO}}$ is formed accompanied by the emission of light. So, compound ‘X’ is magnesium oxide.
If the burning magnesium ribbon is placed in a nitrogen atmosphere, the magnesium nitride ${\text{M}}{{\text{g}}_{\text{3}}}{{\text{N}}_{\text{2}}}$ forms. So, compound ‘Y’ is a magnesium nitride.
When the white compounds magnesium oxide ${\text{MgO}}$ is dissolved in water the magnesium hydroxide forms.
The reaction is represented as follows:
${\text{MgO}}\,\,\,{\text{ + }}\,\,{{\text{H}}_2}{\text{O}} \to \,{\text{Mg}}{\left( {{\text{OH}}} \right)_2}$
So, option (C) is correct.
Additional Information: Option (A) represents the reaction when magnesium ribbon is burnt in oxygen that is the formation of ‘X’ not the reaction of dissolution of ‘X’ so, option (A) is incorrect.
Option (B) represents the reaction when magnesium ribbon is burnt in nitrogen that is the formation of ‘Y’ not the reaction of dissolution of ‘X’ so option (B) is incorrect.
Option (D) represents the reaction on the dissolution of magnesium ribbon in water not the reaction of dissolution of ‘X’ so option (D) is incorrect.
Note: The alkaline earth metal forms ${\text{MO}}$ type oxide. Only the barium is an exception which forms peroxide. The alkaline earth metal forms ${{\text{M}}_3}{{\text{N}}_2}$ type nitrides. The alkaline earth metal forms ${\text{M}}{\left( {{\text{OH}}} \right)_2}$ type hydroxides.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

Who Won 36 Oscar Awards? Record Holder Revealed

What is the median of the first 10 natural numbers class 10 maths CBSE

Why is it 530 pm in india when it is 1200 afternoon class 10 social science CBSE

Why is there a time difference of about 5 hours between class 10 social science CBSE

What is the full form of POSCO class 10 social science CBSE

