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A lift of mass 1000 Kg which is moving with acceleration 1 m/$s^2$ in upward direction, then the tension developed in string which is connected to lift is:
$\left( A \right)$ 9,800 N
$\left( B \right)$ 10,800 N
$\left( C \right)$ 11,000 N
$\left( D \right)$ 10,000 N

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Last updated date: 27th Mar 2024
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MVSAT 2024
Answer
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- Hint: In this question, use the property that the net acceleration working on the lift is the sum of the acceleration of the lift and the acceleration due to gravity so use this concept to reach the solution of the question.

Complete step-by-step solution -

According to Newton's second law of motion the force acting on the object is the product of object mass and the net acceleration working on the object.
$ \Rightarrow F = m\left( {{a_{net}}} \right)$
As the lift goes upward (i.e. it is working against the Earth’s gravity) so the total acceleration acting on the lift is the sum of Earth gravity and the acceleration of the lift by which it is going upwards.
Now as we know earth gravity g = 9.8 m/$s^2$.
And it is given that the lift is moving upward with an acceleration of 1 m/$s^2$.
So the net acceleration working on the lift is \[\left( {9.8 + 1} \right) = 10.8\] m/$s^2$.
And it is also given that the mass of the lift is 1000 kg
So the force acting on the lift is
$F = 1000 \times 10.8 = 10800$N
Now the force acting on the lift is the same as tension developed in the string which is connected to the lift as these forces are equal in nature whenever any object is lifted by the cable or string. So the tension working on the string is the same as the force exerted on the object.
So the tension acting on the string = 10,800 N.
So this is the required answer.
Hence option (B) is the correct answer.

Note: Whenever we face such types of question the key concept we have to remember is that the net acceleration acting on the body is the sum of acceleration of the object and the and the acceleration due to gravity i.e. Earth’s gravity when the object is moving upwards and when the object is moving downwards the net acceleration acting on the body is the difference of acceleration due to gravity and the and the acceleration of the object.
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