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A geyser is rated $1500W,250V$. It is connected to $250V$ mains.
Calculate:
$(i)$ The Current drawn.
$(ii)$ The energy consumed in $50hrs$.
$(iii)$ the cost of energy consumed at $Rs2.20$per $KWh$

Answer
VerifiedVerified
566.7k+ views
Hint: Here we know the power value, time voltage, so by using a unique formula according to an electrical circuit, we can measure the above statements, the ammeter is connected in series while the voltmeter is connected in parallel. Then find the value to change the formula for our reference.
Useful formula:
The power is defined as,
$P = VI$
Where,
$P = $ power
$V = $ voltage
$I = $ current
Energy Is defined as,
$E = P \times T$
Where,
$E = $ energy
\[T = \] Time

Complete answer:
Given by,
Power $P = 1500W$
Voltage $V = 250V$
Now,
We need to calculate.
$(i)$ The current drawn
We know that formula of current,
Here,
$P = VI$
We know the value of $P$ and $V$
So, we rearranging the following equation,
The current is equal to the power divided by the voltage
$I = \dfrac{P}{V}$
Substituting the given value in above formula,
We get,
$I = \dfrac{{1500}}{{250}}$
On simplifying,
$I = 6A$
Thus, the current drawn is $6A$
We need to calculate the energy consumed in $50hrs$
$(ii)$ The energy consumed in $50hrs$.
Energy is defined as,
According to the formula
$E = P \times T$
Here,
We substituting the $P$ value in above formula,
We get,
$E = VI \times T$
Substituting the given value in above formula,
$250 \times 6 \times 50$
On simplifying,
$E = 7500W - h$
Here,
Thus, the energy consumed in $50hrs$ is $75kW - h$.
$(iii)$ The cost of energy consumed of $2.20$ per unit.
We need to calculate the total cost
The total cost $ = 2.20 \times 75$
Hence,
The current energy consumed in $50hours$ and total cost are $6A$.
$75W - h$ and $165Rs$

Note:
One of the types of energy that requires the movement of electrons is electricity. It is the most widely used source of energy and a fundamental part of nature. the production of electricity occurs. Volt is a joule per coulomb since, while coulomb is a unit for the charge, joule is a unit of work performed.