
When a force of 1 newton acts on a mass of 1 kg that is able to move freely, the object moves with a(n):
(A) Speed of $ 1m{s^{ - 1}}$
(B) Acceleration of $1m{s^{ - 2}}$
(C) Speed of $1 km{s^{ - 1}}$
(D) None of these
Answer
594.9k+ views
Hint:Relation between force, mass and acceleration. Mass is defined as the amount of matter present in it and acceleration is the change in velocity per unit time.
Formula Used:
F = ma
Here, F= Force acting on a body
m=mass of the body
a= acceleration acting on the body
Complete step by step answer:
Force is defined as the product of mass and acceleration i.e. F = ma where F is force, m is mass and a is acceleration. This relation is being derived from Newton's second law of motion. One newton is that force which when acting on a body of mass 1 kg, produces an acceleration of $1m{s^{ - 2}}$.
Numerically, F = 1 N [ N is the symbol of Newton], m = 1 kg
$F = ma$
Now, We will put the values in the given formula
$1N = 1kg \times a$
$a = \dfrac{{1N}}{{1kg}}$
$a = \dfrac{{1 kg m{s^{ - 2}}}}{{1kg}}$
$a = 1m{s^{ - 2}}$
Hence, option (B) is correct.
Additional information:
$F = ma$ is Newton’s second law only in a special case when mass m of the body is constant at velocity v (which is much smaller than the velocity of light c). But its second law in the form F is equal to Change in momentum divided by change in time is true in all situations and thus it is one of the fundamental laws of Physics.
Note: Both force and acceleration are vector quantities. The acceleration is positive as it is in the direction of force. When a force of 1 N is applied on a body of mass 1 kg, acceleration is $1m{s^{ - 1}}$.
Formula Used:
F = ma
Here, F= Force acting on a body
m=mass of the body
a= acceleration acting on the body
Complete step by step answer:
Force is defined as the product of mass and acceleration i.e. F = ma where F is force, m is mass and a is acceleration. This relation is being derived from Newton's second law of motion. One newton is that force which when acting on a body of mass 1 kg, produces an acceleration of $1m{s^{ - 2}}$.
Numerically, F = 1 N [ N is the symbol of Newton], m = 1 kg
$F = ma$
Now, We will put the values in the given formula
$1N = 1kg \times a$
$a = \dfrac{{1N}}{{1kg}}$
$a = \dfrac{{1 kg m{s^{ - 2}}}}{{1kg}}$
$a = 1m{s^{ - 2}}$
Hence, option (B) is correct.
Additional information:
$F = ma$ is Newton’s second law only in a special case when mass m of the body is constant at velocity v (which is much smaller than the velocity of light c). But its second law in the form F is equal to Change in momentum divided by change in time is true in all situations and thus it is one of the fundamental laws of Physics.
Note: Both force and acceleration are vector quantities. The acceleration is positive as it is in the direction of force. When a force of 1 N is applied on a body of mass 1 kg, acceleration is $1m{s^{ - 1}}$.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

The largest wind power cluster is located in the state class 11 social science CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

What steps did the French revolutionaries take to create class 11 social science CBSE

Which among the following are examples of coming together class 11 social science CBSE

