 QUESTION

# A flooring tile has a shape of parallelogram whose base is 18 cm and the corresponding height is 6 cm. How many such tiles are required to cover a floor of area $540{{m}^{2}}$. (If required you can split the tiles in whatever way you want to fill up the corners)

Hint: In this problem we are given the base and height of a parallelogram. Using this data, we can calculate the individual tile area which is in shape of a parallelogram. Dividing it with the given area in the problem statement will give the number of tiles involved.

In this question, first we find the area of parallelogram using the formula $b\times h$ where b is the base and h is the height of the parallelogram.
As, we know that $1m=100cm$. Using this, first we convert the base of parallelogram and height of parallelogram from centimeters to meters.
Base of parallelogram$=18cm=0.18m$.
Height of parallelogram$=6cm=0.06m$.
Area of parallelogram$=b\times h=0.18\times 0.06$.
Area of parallelogram$=0.0108{{m}^{2}}$.
Now, the number of tiles required can be expressed as $\dfrac{Area\text{ }of\text{ floor}}{Area\text{ of each tile}}$.
Number of tiles required$=\dfrac{540{{m}^{2}}}{0.0108{{m}^{2}}}=50000$ tiles.
Hence, the number of tiles required to cover a floor of $540{{m}^{2}}$ is 50000.