Question

A drum contained 200 litres of water. 7 litres of water was lost due to leakage. What percent of water remained in the drum?

Answer 1

Hint- To evaluate the percentage of water remained in the drum first determine the ratio of the remaining quantity of water to the total quantity of water and then multiply it by $100$.

Complete step-by-step solution:
We are given that a drum contained $200\,litres$ water and due to some leakage$7\,litres$ of water was lost.
We have to find the percent of water remaining in the drum.
First, we evaluate the quantity of water which remains in the drum.
For this, subtract the quantity of water which lost due to some leakage from the total quantity of water given in the question.
$200 - 7 = 193\,litres$
It means $193\,litres$ of water remained in the drum.
Now we have to evaluate the percentage of water left in the drum.
We know that to evaluate the percentage of anything first we write the quantities in rational number form in which the required quantity is written in the numerator and total quantity is written in the denominator and then multiply this rational number by $100$.
In this case, the required quantity of water is $193\,litres$ and the total quantity of water is$200\,litres$.
Evaluate the percentage of water left according to the given definition of percentage.

\[\dfrac{{193}}{{200}} \times 100 = 96.5\,\% \]
Hence, the percentage of water left in the drum is $96.5\% $
Note: We can solve this question by another approach. In the percentage question the total quantity represents $100\% $ it means the value of $200$is $100\% $.
Evaluate the value of $193$ i.e..,
\[
  200 \to 100\% \\
  1 \to \dfrac{{100}}{{200}} \\
  193 \to \dfrac{{100}}{{200}} \times 193 = 96.5\% \\
\]