Question

A die is thrown once. Find the probability of getting a number lying between 2 and 6.

Answer 1

Hint: To find the probability, we find the total number of favorable outcomes and then we find the total number of possible outcomes. Then we use the formula for probability i.e.
Probability =$\dfrac{{{\text{number of favorable outcomes}}}}{{{\text{Total number of outcomes}}}}$.

Complete step-by-step answer:
A die is rolled once is an independent event which has 6 different possibilities.
Number of outcomes = 6

Now, Probability of getting a number lying between 2 and 6.
I.e. the numbers 3, 4 or 5.
Number of favorable outcomes = 3
We know the formula of probability is given as,
Probability =$\dfrac{{{\text{number of favorable outcomes}}}}{{{\text{Total number of outcomes}}}}$.
Therefore the Probability of getting a number between 2 and 6 = $\dfrac{3}{6} = \dfrac{1}{2}$

Note - The key in solving such types of problems is to look for the perfect formula and proceed accordingly. Exactly counting the total number of favorable outcomes and total number of possible outcomes is crucial. The numbers lying between 2 and 6 only refer to the numbers in between them (3, 4 and 5) but not the numbers 2 and 6 themselves.