Question

A die is thrown once. Find the probability of getting an odd number.

Answer 1

Hint- In order to solve the problem use the basic definition of probability. First count the total number of outcomes possible in this event. Then count the number of favorable outcomes for the result. Finally use the basic formula and find the ratio.

Complete step-by-step answer:
Given statement: A die is thrown once.
As we know that when a die is thrown possible outcomes that we can get are:
$\left\{ {1,2,3,4,5,6} \right\}$
Therefore, total number of outcomes = 6
We know that out of these results the odd results are:
$\left\{ {1,3,5} \right\}$
So, number of favorable outcomes = 3
As we know the basic formula for the probability of event is:
${\text{Probability of an event}} = \dfrac{{{\text{Number of favorable outcomes}}}}{{{\text{Total number of outcomes}}}}$
Now let us substitute the values to find the answer
$
   \Rightarrow P\left( {{\text{odd number}}} \right) = \dfrac{{{\text{Number of favorable outcomes}}}}{{{\text{Total number of outcomes}}}} \\
   \Rightarrow P\left( {{\text{odd number}}} \right) = \dfrac{{\text{3}}}{{\text{6}}} \\
   \Rightarrow P\left( {{\text{odd number}}} \right) = \dfrac{1}{2} \\
 $
Hence, the probability of getting an odd number in single throw of die is $\dfrac{1}{2}$

Note- The probability of an event is the measure of the chance that the event will occur as a result of an experiment. The probability of an event A is the number of ways event A can occur divided by the total number of possible outcomes. In order to solve these types of problems students can use the method of sample space and counting.