Question

A class has $30$ girls and $25$ boys. What is the percentage of boys and girls in the class?

Answer 1

Hint: First, we need to know about the concepts of the percentage, so that we are able to solve the given problem easily. The percentage is the mathematical concept which is to measure the proportion of the given values in any term of the original value. The percentage is a relative value that indicates the hundredth parts of any quantity.
Like $70\% $ of $40$ is $28$. This can be obtained by $40 \times \dfrac{{70}}{{100}} = 28$ where $70$ represents the percent, $40$ is the base and $28$ is the part.
Formula used: Find the overall value (boys and girls) then we have $\dfrac{B}{{B + G}} \times 100,\dfrac{G}{{B + G}} \times 100$ is the percentage formula to obtain the result.

Complete step-by-step solution:
Since the class has $30$ girls and $25$ boys. Then the overall student is the class can be calculated using the addition operation, which is $30 + 25 = 55$
Hence to find the boys percentage in the class is $\dfrac{B}{{B + G}} \times 100$ where B is the number of boys given as $25$ and $B + G$ is the total number of students founded as $55$
Hence, we have the boy’s percentage as $\dfrac{B}{{B + G}} \times 100 = \dfrac{{25}}{{55}} \times 100$
By the multiplication operation, we have $\dfrac{B}{{B + G}} \times 100 = \dfrac{{25}}{{55}} \times 100 = \dfrac{{2500}}{{55}}$
By the division operation, we get $\dfrac{B}{{B + G}} \times 100 = \dfrac{{2500}}{{55}} = 45.45\% $
similarly to find the girls percentage in the class is $\dfrac{G}{{B + G}} \times 100$ where G is the number of boys given as $30$ and $B + G$ is the total number of students founded as $55$
Hence, we have the boy’s percentage as $\dfrac{{30}}{{B + G}} \times 100 = \dfrac{{30}}{{55}} \times 100$
By the multiplication operation, we have $\dfrac{G}{{B + G}} \times 100 = \dfrac{{30}}{{55}} \times 100 = \dfrac{{3000}}{{55}}$
By the division operation, we get $\dfrac{G}{{B + G}} \times 100 = \dfrac{{3000}}{{55}} = 54.55\% $
Hence the percentage of the boys in the class is $45.45\% $ and the girls is $54.55\% $

Note: The mathematical operation which we used in the given problem is Addition, multiplication, and division.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to the number that multiplies the first number. Have a look at an example; while multiplying $5 \times 7$ the number $5$ is called the multiplicand and the number $7$ is called the multiplier.
The process of the inverse of the multiplication method is called division. Like $x \times y = z$is multiplication thus the division sees as $x = \dfrac{z}{y}$.
Also, the other two operations, Addition is the summing of two or more than two numbers, or values, or variables, and in addition, if we sum the two or more numbers a new frame of the number will be found, also in subtraction which is the minus of two or more than two numbers or values example $2 - 3 = - 1$ (larger number signs stays constant)