Question

A card is drawn from a well shuffled pack of cards. The probability of getting a queen of club or king of heart is
A. $\dfrac{1}{52}$
B. $\dfrac{1}{26}$
C. $\dfrac{1}{18}$
D. None of these

Answer 1

Hint: We first explain the concept of empirical probability and how the events are considered. We take the given events and find the number of outcomes. Using the probability theorem of $P\left( A \right)=\dfrac{n\left( A \right)}{n\left( U \right)}$, we get the empirical probability of the shooting event.

Complete step by step answer:
Empirical probability uses the number of occurrences of an outcome within a sample set as a basis for determining the probability of that outcome.
We take two events, one with conditions and another one without conditions. The later one is called the universal event which chooses all possible options.
We find the number of outcomes for both events. We take the conditional event $A$ as a drawn card to be a queen of the club or king of heart and the universal event $U$ as drawing a card and numbers will be denoted as $n\left( A \right)$ and $n\left( U \right)$.
We take the empirical probability of the given problem as $P\left( A \right)=\dfrac{n\left( A \right)}{n\left( U \right)}$.
A well shuffled pack of cards contains 52 cards. Therefore, if the condition of a drawn card is a queen of club or king of heart, then $n\left( A \right)=2$ and $n\left( U \right)={}^{52}{{C}_{1}}=52$.
The empirical probability is $P\left( A \right)=\dfrac{2}{52}=\dfrac{1}{26}$.The correct option is option (B).

Note:
We need to understand the concept of the universal event. This will be the main event that is implemented before the conditional event. Empirical probabilities, which are estimates, calculated probabilities involving distinct outcomes from a sample space are exact.