A body slipping on a rough horizontal plane moves with a deceleration of $4.0m/{s^2}$ What is the coefficient of kinetic friction between the block and the plane?
Answer
584.4k+ views
Hint: We know that friction is a contact force along the tangent to the contacting the surfaces to destroy the relative motion between them. When objects are placed on each other and the system slides down on a horizontal road, a force is acting vertically and horizontally on the system. Then using the above determines its coefficient of kinetic friction.
Formula:
$f = \mu N$
Where $\mu $ is coefficient of friction, $f$ is the frictional force, $N$ is the Normal force.
Complete step by step answer:
• Friction is the force in which opposition comes between two surfaces so as to impede the relative motion between them.
• Friction is regarded as an electromagnetic force. Friction can also be due to the forces among molecules at close proximities.
• The surface will slip on each other without opposition in the absence of friction. This may be producing a dangerous motion.
• Polishing the machine, using lubricants on the machine, using ball bearing, streamlining can reduce friction.
• The resistance by a body in a static condition while it tends to be move under the action of external force
• This resistance is called static frictional force. The ratio of limiting friction (maximum static friction) to normal reaction is called coefficient of static friction. It is a unit less quantity.
Frictional force is given by
$F = ma$
Here $a = 4m/{s^2}$
Then $F = 4mN$
The normal force is equal to $mg$
Then we know $F = \mu N$
$\mu = \dfrac{{4m}}{{mg}} = \dfrac{4}{{10}} = 0.4$
Hence coefficient of kinetic friction is $0.4$.
Note: The surfaces will slip on each other without opposition in the absence of friction. This may be producing a dangerous motion. Polishing the machine, using lubricants on the machine, using ball bearing, streamlining can reduce friction. The way that is effective to reduce friction is to place a thin cushion of air maintained between the solid surfaces in relative motion.
Formula:
$f = \mu N$
Where $\mu $ is coefficient of friction, $f$ is the frictional force, $N$ is the Normal force.
Complete step by step answer:
• Friction is the force in which opposition comes between two surfaces so as to impede the relative motion between them.
• Friction is regarded as an electromagnetic force. Friction can also be due to the forces among molecules at close proximities.
• The surface will slip on each other without opposition in the absence of friction. This may be producing a dangerous motion.
• Polishing the machine, using lubricants on the machine, using ball bearing, streamlining can reduce friction.
• The resistance by a body in a static condition while it tends to be move under the action of external force
• This resistance is called static frictional force. The ratio of limiting friction (maximum static friction) to normal reaction is called coefficient of static friction. It is a unit less quantity.
Frictional force is given by
$F = ma$
Here $a = 4m/{s^2}$
Then $F = 4mN$
The normal force is equal to $mg$
Then we know $F = \mu N$
$\mu = \dfrac{{4m}}{{mg}} = \dfrac{4}{{10}} = 0.4$
Hence coefficient of kinetic friction is $0.4$.
Note: The surfaces will slip on each other without opposition in the absence of friction. This may be producing a dangerous motion. Polishing the machine, using lubricants on the machine, using ball bearing, streamlining can reduce friction. The way that is effective to reduce friction is to place a thin cushion of air maintained between the solid surfaces in relative motion.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Discuss the various forms of bacteria class 11 biology CBSE

