
A block weighs \[15N\] in air and \[12N\] when immersed in water. The specific gravity of the block is,
A. \[0.8\]
B. \[0.25\]
C. \[\dfrac{5}{4}\]
D. \[5\]
Answer
573k+ views
Hint: Here the weights of a block in two different mediums are given. We need to find the specific gravity of the block. Specific gravity or relative density of an object is the ratio of weight of the body in air to apparent loss of weight in water. By using this equation, we can find the specific gravity of the block.
Formula used:
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
Complete step by step answer:
Given,
\[\text{Weight of block in air = 15N}\]
\[\text{Weight of block in water = 12N}\]
We know,
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
\[\text{Apparent loss of weight in water = }\!\!~\!\!\text{ Weight in air - Weight in water = 15-12 =3N}\]
Then,
\[\text{Specific gravity = }\dfrac{15}{3}=5\]
Answer is option D.
Additional information:
Density of a substance is defined as the ratio of mass to volume. A change in volume of the substance will result in change in its density. It is the measure of matter within a given area. Density of a substance is a unique number. Wherein, relative density or specific gravity of an object is defined as the ratio of density of the object in air to the density of water at \[\text{4}{}^\circ \text{C}\]. It can be measured in many ways.
\[\text{Specific gravity = }\dfrac{\text{Density of object in air}}{\text{Density of water at 4}{}^\circ \text{C}}\]
Or,
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
Or
\[\text{Specific gravity = }\dfrac{\text{Mass of substance}}{\text{Mass of equal volume of water at 4}{}^\circ \text{C}}\]
Note:
Value of relative density is the same in all systems of measurement. Since, it is the ratio of two similar quantities, the relative density doesn’t have a unit. It is a pure number. It tells us how many times an object is heavier than water. Relative density of a substance can be found or compared with numerous other reference bodies. If the relative density of a substance is less than one it will float on that reference object.
Formula used:
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
Complete step by step answer:
Given,
\[\text{Weight of block in air = 15N}\]
\[\text{Weight of block in water = 12N}\]
We know,
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
\[\text{Apparent loss of weight in water = }\!\!~\!\!\text{ Weight in air - Weight in water = 15-12 =3N}\]
Then,
\[\text{Specific gravity = }\dfrac{15}{3}=5\]
Answer is option D.
Additional information:
Density of a substance is defined as the ratio of mass to volume. A change in volume of the substance will result in change in its density. It is the measure of matter within a given area. Density of a substance is a unique number. Wherein, relative density or specific gravity of an object is defined as the ratio of density of the object in air to the density of water at \[\text{4}{}^\circ \text{C}\]. It can be measured in many ways.
\[\text{Specific gravity = }\dfrac{\text{Density of object in air}}{\text{Density of water at 4}{}^\circ \text{C}}\]
Or,
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
Or
\[\text{Specific gravity = }\dfrac{\text{Mass of substance}}{\text{Mass of equal volume of water at 4}{}^\circ \text{C}}\]
Note:
Value of relative density is the same in all systems of measurement. Since, it is the ratio of two similar quantities, the relative density doesn’t have a unit. It is a pure number. It tells us how many times an object is heavier than water. Relative density of a substance can be found or compared with numerous other reference bodies. If the relative density of a substance is less than one it will float on that reference object.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Difference Between Prokaryotic Cells and Eukaryotic Cells

