
A block weighs \[15N\] in air and \[12N\] when immersed in water. The specific gravity of the block is,
A. \[0.8\]
B. \[0.25\]
C. \[\dfrac{5}{4}\]
D. \[5\]
Answer
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Hint: Here the weights of a block in two different mediums are given. We need to find the specific gravity of the block. Specific gravity or relative density of an object is the ratio of weight of the body in air to apparent loss of weight in water. By using this equation, we can find the specific gravity of the block.
Formula used:
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
Complete step by step answer:
Given,
\[\text{Weight of block in air = 15N}\]
\[\text{Weight of block in water = 12N}\]
We know,
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
\[\text{Apparent loss of weight in water = }\!\!~\!\!\text{ Weight in air - Weight in water = 15-12 =3N}\]
Then,
\[\text{Specific gravity = }\dfrac{15}{3}=5\]
Answer is option D.
Additional information:
Density of a substance is defined as the ratio of mass to volume. A change in volume of the substance will result in change in its density. It is the measure of matter within a given area. Density of a substance is a unique number. Wherein, relative density or specific gravity of an object is defined as the ratio of density of the object in air to the density of water at \[\text{4}{}^\circ \text{C}\]. It can be measured in many ways.
\[\text{Specific gravity = }\dfrac{\text{Density of object in air}}{\text{Density of water at 4}{}^\circ \text{C}}\]
Or,
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
Or
\[\text{Specific gravity = }\dfrac{\text{Mass of substance}}{\text{Mass of equal volume of water at 4}{}^\circ \text{C}}\]
Note:
Value of relative density is the same in all systems of measurement. Since, it is the ratio of two similar quantities, the relative density doesn’t have a unit. It is a pure number. It tells us how many times an object is heavier than water. Relative density of a substance can be found or compared with numerous other reference bodies. If the relative density of a substance is less than one it will float on that reference object.
Formula used:
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
Complete step by step answer:
Given,
\[\text{Weight of block in air = 15N}\]
\[\text{Weight of block in water = 12N}\]
We know,
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
\[\text{Apparent loss of weight in water = }\!\!~\!\!\text{ Weight in air - Weight in water = 15-12 =3N}\]
Then,
\[\text{Specific gravity = }\dfrac{15}{3}=5\]
Answer is option D.
Additional information:
Density of a substance is defined as the ratio of mass to volume. A change in volume of the substance will result in change in its density. It is the measure of matter within a given area. Density of a substance is a unique number. Wherein, relative density or specific gravity of an object is defined as the ratio of density of the object in air to the density of water at \[\text{4}{}^\circ \text{C}\]. It can be measured in many ways.
\[\text{Specific gravity = }\dfrac{\text{Density of object in air}}{\text{Density of water at 4}{}^\circ \text{C}}\]
Or,
\[\text{Specific gravity = }\dfrac{\text{Weight of object in air}}{\text{Apparent loss of weight in water}}\]
Or
\[\text{Specific gravity = }\dfrac{\text{Mass of substance}}{\text{Mass of equal volume of water at 4}{}^\circ \text{C}}\]
Note:
Value of relative density is the same in all systems of measurement. Since, it is the ratio of two similar quantities, the relative density doesn’t have a unit. It is a pure number. It tells us how many times an object is heavier than water. Relative density of a substance can be found or compared with numerous other reference bodies. If the relative density of a substance is less than one it will float on that reference object.
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