Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

A 10mg effervescent tablet containing sodium bicarbonate and oxalic acid releases 0.25ml of CO2 at T=298.15K and p=1bar. If molar volume of CO2 is 25.9L under such conditions, what is the percentage of sodium carbonate in each tablet?
(Molar mass of NaHCO3 is 84g/mol)
A.16.8
B.8.4
C.0.84
D.33.6

Answer
VerifiedVerified
505.8k+ views
like imagedislike image
Hint: To calculate the percentage of sodium carbonate in the tablet first calculate the relation between the number of moles of sodium carbonate and number of moles of carbon dioxide then apply the mole concept.

Complete step by step answer:
First we will talk about how to calculate the number of moles.
Number of moles: Number of moles can be defined as the ratio of given mass to the molar mass of the substance. Or we can find the number of moles of a substance by the ratio of given volume to the molar volume.
In the question it is given that the molar volume of carbon dioxide is 25.9L and the volume of carbon dioxide produced is 0.25ml. So number of moles =given volumemolar volume
n=0.25×10325.9105
The reaction of sodium bicarbonate with oxalic acid is as
2NaHCO3+H2C2O42NaC2O4+2H2O+2CO2
By the reaction, it is clear that two moles of sodium bicarbonate are forming two moles of carbon dioxide. Hence one mole of sodium bicarbonate will form one mole of carbon dioxide.
We already calculated the number of moles of carbon dioxide i.e. 105.
And the number of moles of sodium bicarbonate and number of moles of carbon dioxide are the same. So the number of moles of sodium bicarbonate will be 105. Now the molar mass of sodium bicarbonate is 84g/mol.
So the mass of sodium bicarbonate present will be as molar mass multiply number of moles i.e. 84×105g
Now, the percentage of mass i.e. %mass =84×10510×103×100=8.4%.
Hence, the correct answer is option B.

Note:
 If we want to calculate a given mass and if we have a number of moles and molar mass of the substance then we can calculate the required mass as: number of moles multiply by molar mass of the substance.
Latest Vedantu courses for you
Grade 8 | CBSE | SCHOOL | English
Vedantu 8 CBSE Pro Course - (2025-26)
calendar iconAcademic year 2025-26
language iconENGLISH
book iconUnlimited access till final school exam
tick
School Full course for CBSE students
EnglishEnglish
MathsMaths
ScienceScience
₹49,800 (9% Off)
₹45,300 per year
EMI starts from ₹3,775 per month
Select and buy