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\[75.2{\text{ }}g\] of \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}{\text{OH}}\] (Phenol) is dissolved in a solvent of \[{{\text{K}}_{\text{f}}}{\text{ = 14}}\], If the depression in freezing point is \[{\text{7K}}\] then find the \[{\text{\% }}\] of phenol that dimerises.

Answer
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Hint: Dimerise means combining with similar molecules to form a dimer. In this question a phenol dimer is being formed and to calculate the percentage of phenol which formed a dimer, find the degree of dissociation.

Complete step by step answer:
Let’s start with discussing a little about the freezing point depression. According to the concept of freezing point depression whenever a solute is added to a pure solvent, the freezing point of the solvent (which is now a solution) decreases. For example, when \[{\text{NaCl}}\] is dissolved in pure water, the freezing point of water is reduced from \[{{\text{0}}^{\text{o}}}{\text{C}}\] to - \[{21.1^o}C\] (Max).
Coming back to the question we are given an unknown solvent in which we are adding \[75.2{\text{ }}g\] of Phenol. The \[{{\text{K}}_{\text{f}}}\] of the solvent is \[{\text{14}}\]. The depression given to us is \[{\text{7K}}\] and we have to find the \[{\text{% }}\] of phenol that dimerises.
The equilibrium that must have establish between different phenol molecules is given:
\[{\text{2}}{{\text{C}}_{{\text{6}}}}{{\text{H}}_{{\text{5}}}}{\text{OH}}\underset {} \leftrightarrows {{\text{(}}{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{5}}}}{\text{OH)}}_{\text{2}}}\]
The molecular mass of phenol is \[94.11{\text{g/mol}}\]. So, the amount of Phenol added in solvent in moles will be
$\dfrac{{{\text{Given Mass}}}}{{{\text{Molecular Mass}}}}{\text{ = }}\dfrac{{75.2}}{{94.11}} = 0.8{\text{ moles}}$
If $\alpha $ is the degree of dissociation, then the van't hoff factor I will be $\left( {\dfrac{{2 - \alpha }}{2}} \right)$
Also, the depression in freezing point is given by \[{{\text{K}}_{\text{f}}}\] \[{\text{X}}\] moles \[{\text{X i}}\]
Which will be, Depression in freezing point $ = 7 = 14 \times 0.8\left( {\dfrac{{2 - \alpha }}{2}} \right)$
Solving this we will get $\alpha = 0.75$, which means \[75\% \] of phenol is dimerises.

Note:
Since we know that, Phenol is an alcoholic ring compound with the molecular formula of C6H5OH. This molecule is being used as a disinfectant, slimicide and antiseptic. Slimicides are the chemicals which are used to kill slime forming organisms like bacteria and fungi. Phenol is also used in the preparation of mouthwash.