Question

When $5.0\;{\rm{gram}}$ of ${\rm{BaC}}{{\rm{l}}_{\rm{2}}}$ is dissolved in water to have ${10^6}$ gram of solution. The concentration of a solution is:
A. ${\rm{2}}{\rm{.5}}\;{\rm{ppm}}$
B. $5\;{\rm{ppm}}$
C. $5\;{\rm{M}}$
D. $5\;{\rm{g}}\;{{\rm{L}}^{ - 1}}$

Answer 1

Hint:
We know that the concentration is the mixture of the solution's volume and moles. Generally, it can be measured in M and ppm. The mass or weight of solute and solution both placed a very important role when we determined the concentration in the unit that is ppm.
The ppm is the abbreviation form of parts per millions and it commonly expressed the ratio of mass that is mg/L.

Complete step by step solution
The given mass of barium chloride solution is $5\;{\rm{g}}$ and the mass of the solution is ${10^6}$ gram.
The unknown concentration of the solution can be calculated by using the formula as shown below.
${\rm{C}} = \dfrac{{\rm{m}}}{{\rm{M}}}{\rm{ \times 1}}{{\rm{0}}^{\rm{6}}}$
Where, c is the concentration in ppm, m is the mass of solute in grams and M is the mass of the solution in grams.
The value of mass of the solute that is barium chloride in gram is $5\;{\rm{g}}$ and the mass of the solution (when the solute barium chloride dissolved in the aqueous water) in grams is ${10^6}$ gram.
Now, let’s substitute the respective values in the above equation. We get,
$
{\rm{Concentration}}\;{\rm{in}}\;{\rm{ppm}} = \dfrac{{\rm{5}}}{{{\rm{1}}{{\rm{0}}^{\rm{6}}}}} \times {\rm{1}}{{\rm{0}}^{\rm{6}}}\\
 = 5\;{\rm{ppm}}
$
Hence, the correct option for this question is C that is ${\rm{5}}\;{\rm{ppm}}$,

Note:
The concentration is one of the physical quantities. It can be affected by temperature. When the amount of volume and number of moles changes, the concentration of that solution will also change or be affected. The concentration is directly proportional to the number of moles and inversely proportional to the solution's value.