How many 3-digit numbers are divisible by 6 in all?
(a)149
(b)150
(c)151
(d)166
Answer
554.7k+ views
Hint: To solve the question, we have to calculate the smallest 3-digit number divisible by 6 and the largest 3-digit number divisible by 6. To calculate the number of 3-digit numbers is divisible by 6, substitute the obtained smallest and largest 3-digit number value in the formula.
Complete step-by-step answer:
We know,
The smallest 3-digit number is 100.
The largest 3-digit number is 999.
The smallest 3-digit number divisible by 6 is 102.
The largest 3-digit number divisible by 6 is 996.
We know that the number of numbers between ‘a’ and ‘b’ divisible by n is equal to \[\left( \dfrac{a-b}{n} \right)+1\] such that a, b are multiples of n and a > b.
When compared with the obtained data, we get
The value of a = 996.
The value of b = 102.
The value of n = 6.
By substituting the values in the given equation, we get
The number of between 996 and 102 divisible by 6 is equal to
\[\begin{align}
& \left( \dfrac{996-102}{6} \right)+1 \\
& =\left( \dfrac{894}{6} \right)+1 \\
\end{align}\]
\[\begin{align}
& =\left( \dfrac{6\times 149}{6} \right)+1 \\
& =149+1 \\
& =150 \\
\end{align}\]
Thus, the number of 3-digit numbers divisible by 6 is 150.
Hence, option (b) is the right choice.
Note: The possibility of mistake can be made using the general method by calculating all the possible numbers which are divisible by 6, which will increase the procedure of solving since the 3-digit multiples of 6 are large in number. The alternative way of solving can be by calculating the 3-digit numbers which are divisible by 2 and the 3-digit numbers which are divisible by 3. The numbers which are divisible by 2 and 3 are divisible by 6. Thus, we can arrive at the answer.
Complete step-by-step answer:
We know,
The smallest 3-digit number is 100.
The largest 3-digit number is 999.
The smallest 3-digit number divisible by 6 is 102.
The largest 3-digit number divisible by 6 is 996.
We know that the number of numbers between ‘a’ and ‘b’ divisible by n is equal to \[\left( \dfrac{a-b}{n} \right)+1\] such that a, b are multiples of n and a > b.
When compared with the obtained data, we get
The value of a = 996.
The value of b = 102.
The value of n = 6.
By substituting the values in the given equation, we get
The number of between 996 and 102 divisible by 6 is equal to
\[\begin{align}
& \left( \dfrac{996-102}{6} \right)+1 \\
& =\left( \dfrac{894}{6} \right)+1 \\
\end{align}\]
\[\begin{align}
& =\left( \dfrac{6\times 149}{6} \right)+1 \\
& =149+1 \\
& =150 \\
\end{align}\]
Thus, the number of 3-digit numbers divisible by 6 is 150.
Hence, option (b) is the right choice.
Note: The possibility of mistake can be made using the general method by calculating all the possible numbers which are divisible by 6, which will increase the procedure of solving since the 3-digit multiples of 6 are large in number. The alternative way of solving can be by calculating the 3-digit numbers which are divisible by 2 and the 3-digit numbers which are divisible by 3. The numbers which are divisible by 2 and 3 are divisible by 6. Thus, we can arrive at the answer.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Convert 200 Million dollars in rupees class 7 maths CBSE

Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE

100 million is equal to begingathered A 1 crore B -class-7-maths-CBSE

List of coprime numbers from 1 to 100 class 7 maths CBSE

There are three types of tickets economy business and class 7 maths CBSE

Write a summary of the poem the quality of mercy by class 7 english CBSE


