
$100c{m^3}$ of a given sample of ${H_2}{O_2}$ gives $1000 \;c{m^3}$ of ${O_2}$ at S.T.P. the given sample is:
A) $10% {H_2}{O_2}$
B) $90% {H_2}{O_2}$
C) $10$ volume ${H_2}{O_2}$
D) $100$ volume ${H_2}{O_2}$
Answer
589.5k+ views
Hint: Hydrogen peroxide is a chemical compound with the formula ${H_2}{O_2}$. ${H_2}{O_2}$ on catalytic Decomposition breaks down to give molecules of water and oxygen ${H_2}$ and ${O_2}$.
Complete answer:
Decomposition is catalysed by various transition metals and their compounds. It is highly unstable in nature and it is stored with a stabilizer in a weakly acidic solution in a dark colored bottle.
he decomposition reaction of ${H_2}{O_2}$ is:
\[{H_2}{O_2} \to {H_2}O + \dfrac{1}{2}{O_2}\]
$\dfrac{1}{2}$ mole of ${O_2}$ is obtained from $34\;g\;{H_2}{O_2}$ .
$1$ ml of ${H_2}{O_2}$ will give $10$ml from ${O_2}$ at STP
10 volume’ means that 10 $cm^3$ of oxygen gas is produced by every 1 $cm^3$ of hydrogen peroxide. Thus for every $100c{m^3}$ the oxygen liberated is $1000c{m^3}$. The sample of ${H_2}{O_2}$ which will be required is
\[\dfrac{{1oooc{m^3}}}{{100c{m^3}}} = 10c{m^3}\]
Hence for the $1000c{m^3}$ of ${O_2}$ 10 times the volume of the sample is required.
Therefore the correct option is option (C) .
Additional Information: Hydrogen peroxide has been used as a propellant in rockets and torpedoes. This is because the decomposition reaction can be speeded up greatly by adding a catalyst. Producing a large volume of gas in a short time and small space creates a lot of energy.
Note: The reaction happens slowly while hydrogen peroxide is stored, because unevenness in the container’s surface can help to split the molecule – one part gets stuck to the surface while the other part pulls away.
Complete answer:
Decomposition is catalysed by various transition metals and their compounds. It is highly unstable in nature and it is stored with a stabilizer in a weakly acidic solution in a dark colored bottle.
he decomposition reaction of ${H_2}{O_2}$ is:
\[{H_2}{O_2} \to {H_2}O + \dfrac{1}{2}{O_2}\]
$\dfrac{1}{2}$ mole of ${O_2}$ is obtained from $34\;g\;{H_2}{O_2}$ .
$1$ ml of ${H_2}{O_2}$ will give $10$ml from ${O_2}$ at STP
10 volume’ means that 10 $cm^3$ of oxygen gas is produced by every 1 $cm^3$ of hydrogen peroxide. Thus for every $100c{m^3}$ the oxygen liberated is $1000c{m^3}$. The sample of ${H_2}{O_2}$ which will be required is
\[\dfrac{{1oooc{m^3}}}{{100c{m^3}}} = 10c{m^3}\]
Hence for the $1000c{m^3}$ of ${O_2}$ 10 times the volume of the sample is required.
Therefore the correct option is option (C) .
Additional Information: Hydrogen peroxide has been used as a propellant in rockets and torpedoes. This is because the decomposition reaction can be speeded up greatly by adding a catalyst. Producing a large volume of gas in a short time and small space creates a lot of energy.
Note: The reaction happens slowly while hydrogen peroxide is stored, because unevenness in the container’s surface can help to split the molecule – one part gets stuck to the surface while the other part pulls away.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

Chemical formula of Bleaching powder is A Ca2OCl2 B class 11 chemistry CBSE

Name the part of the brain responsible for the precision class 11 biology CBSE

The growth of tendril in pea plants is due to AEffect class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

