Answer
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Hint: We should know that the sum of the currents which passes through each path will be equal to the total current that flows from the source. We should be clear about the concept of equivalent resistance in case of parallel and series combinations, to solve this question.
Step by step answer:
It is given in the question that,
${\text{V = 12 volt, I = 1A}}$
Resistance between points A and B is,
${\text{R = 1}}\Omega$
Resistance between points B and C is,
${\text{R = 2}}\Omega$
Resistance between points C and D is,
${\text{R = 6}}\Omega$
Resistance between points D and E is,
$\dfrac{{\text{1}}}{{\text{R}}}{\text{ = }}\dfrac{{\text{1}}}{{{\text{12}}}}{\text{ + }}\dfrac{{\text{1}}}{{\text{4}}}{\text{ }}\left( {{\text{since resistances are in parallel connection}}} \right)$
${\text{or R = 12 }} \times {\text{ }}\dfrac{4}{{12}}{\text{ + 4 = }}\dfrac{{48}}{{16}}{\text{ = 3}}\Omega$
The resistance between points C and D is the highest.
So we can see that the correct answer to the mentioned question is Option C.
Additional Information:
In the case of a parallel circuit the net resistance will always decrease as more components are added. This is because there are more paths for the current to pass through. In the case of the series connection, the electric components are always connected end to end which is along the same line. In this case, the value of the current in the series circuit always remains the same.
Note: In the case of a parallel circuit all the components that are connected will come across each other, forming exactly two sets of the electrical common points. The branch in a parallel circuit is a path in which the electric current formed by one of the load components that have the resistor, flows.The net resistance in the case of a series circuit is always the sum of the individual resistance and is the greater as compared to that of the parallel combination.
Step by step answer:
It is given in the question that,
${\text{V = 12 volt, I = 1A}}$
Resistance between points A and B is,
${\text{R = 1}}\Omega$
Resistance between points B and C is,
${\text{R = 2}}\Omega$
Resistance between points C and D is,
${\text{R = 6}}\Omega$
Resistance between points D and E is,
$\dfrac{{\text{1}}}{{\text{R}}}{\text{ = }}\dfrac{{\text{1}}}{{{\text{12}}}}{\text{ + }}\dfrac{{\text{1}}}{{\text{4}}}{\text{ }}\left( {{\text{since resistances are in parallel connection}}} \right)$
${\text{or R = 12 }} \times {\text{ }}\dfrac{4}{{12}}{\text{ + 4 = }}\dfrac{{48}}{{16}}{\text{ = 3}}\Omega$
The resistance between points C and D is the highest.
So we can see that the correct answer to the mentioned question is Option C.
Additional Information:
In the case of a parallel circuit the net resistance will always decrease as more components are added. This is because there are more paths for the current to pass through. In the case of the series connection, the electric components are always connected end to end which is along the same line. In this case, the value of the current in the series circuit always remains the same.
Note: In the case of a parallel circuit all the components that are connected will come across each other, forming exactly two sets of the electrical common points. The branch in a parallel circuit is a path in which the electric current formed by one of the load components that have the resistor, flows.The net resistance in the case of a series circuit is always the sum of the individual resistance and is the greater as compared to that of the parallel combination.
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