RS Aggarwal Solutions Class 6 Chapter-10 Ratio, Proportion and Unitary Method (Ex 10A) Exercise 10.1 - Free PDF
FAQs on RS Aggarwal Solutions Class 6 Chapter-10 Ratio, Proportion and Unitary Method (Ex 10A) Exercise 10.1
1. What is the correct step-by-step method to find the ratio of two quantities as per the solutions for RS Aggarwal Class 6, Ex 10A?
To find the ratio between two quantities according to the methods in the solutions for Exercise 10A, you should follow these steps:
- First, ensure both quantities are in the same unit. For example, convert both to centimetres or both to metres.
- Write the two quantities as a fraction, with the first quantity as the numerator and the second as the denominator.
- Simplify this fraction to its lowest terms by dividing both the numerator and the denominator by their Highest Common Factor (HCF).
- Finally, write the simplified fraction in the ratio form, using a colon (e.g., a:b).
2. How do the RS Aggarwal solutions for Class 6 Maths Chapter 10 explain the comparison of two different ratios?
The solutions demonstrate a clear method for comparing two ratios. The process is as follows:
- Convert both ratios into their fractional forms (e.g., a:b becomes a/b).
- To compare the fractions, find the Least Common Multiple (LCM) of their denominators.
- Convert each fraction into an equivalent fraction with the LCM as the new denominator.
- The fraction with the larger numerator represents the greater ratio.
3. What is the standard procedure shown in Ex 10A solutions for dividing a certain amount in a given ratio?
To divide a quantity in a given ratio (for example, a:b), the solutions outline this reliable method:
- Find the sum of the terms in the ratio (i.e., a + b). This sum represents the total number of equal parts the quantity is divided into.
- To find the first share, multiply the total quantity by the fraction corresponding to the first term (a / (a+b)).
- To find the second share, multiply the total quantity by the fraction for the second term (b / (a+b)).
4. Why is it crucial to convert quantities to the same unit before finding a ratio, a principle strictly followed in Ex 10A solutions?
It is crucial to convert quantities to the same unit because a ratio is a comparison of like quantities. Comparing '5 metres' to '50 centimetres' directly is meaningless. By converting both to centimetres (500 cm and 50 cm), you create a valid mathematical relationship. The ratio 500:50 (or 10:1) correctly shows that the first length is ten times the second. Without this step, the comparison is fundamentally flawed.
5. How does understanding ratios as fractions in Exercise 10A prepare me for solving proportion problems later in the chapter?
Understanding a ratio like a:b as a fraction a/b is the foundational skill for proportions. A proportion is simply a statement that two ratios are equal (e.g., a:b = c:d), which is written as an equation of two fractions: a/b = c/d. By mastering how to express and simplify ratios in fractional form in Ex 10A, you learn the language needed to set up and solve these proportion equations correctly.
6. What is a common mistake when simplifying ratios in Chapter 10, and how can the RS Aggarwal solutions help prevent it?
A common mistake is incomplete simplification. For instance, a student might simplify the ratio 12:18 to 6:9 by dividing by 2, but forget to simplify it further to 2:3 by dividing by 3. The RS Aggarwal solutions consistently show the process of reducing a ratio to its simplest form by finding the Highest Common Factor (HCF). Following these solved examples helps reinforce the habit of always checking for complete simplification.
7. When dividing an amount in a ratio like 3:5, why do the solutions guide us to use a total of 8 parts (3+5)?
The ratio 3:5 means the whole quantity is conceptually split into two groups of parts. One group contains 3 equal parts and the other contains 5 of the same equal parts. Therefore, the entire quantity consists of a total of 3 + 5 = 8 of these equal parts. To find the value of one part, you must divide the total amount by 8. This logic is the basis of the method for distributing any quantity in a given ratio.






















