## RD Sharma Class 6 Solutions Chapter 9 - Ratio, Proportion and Unitary Method (Ex 9.4) Exercise 9.4 - Free PDF

## FAQs on RD Sharma Class 6 Solutions Chapter 9 - Ratio, Proportion and Unitary Method (Ex 9.4) Exercise 9.4

**1. Where can I find exercise solutions and revision notes for RD Sharma Maths Class 6 Chapter 9- Ratio, Proportion, and Unitary Method?**

For free access to RD Sharma Maths Class 6 Chapter 9, exercises solutions and revision notes, one can visit Vedantu’s website. All the exercise solutions and revision notes of Vedantu are prepared by subject experts in the right conceptual and step-by-step manner. Students can also download the pdf form of the exercise solution and revision notes if they choose to study offline. The study can rely on revision notes provided by Vedantu for exams as well because a detailed explanation of each concept is given.

**2. Where is the Unitary Method used in Real-Life practices?**

Unitary Method is used in our day to day life as well such as

To find how much petrol will our car need for 20 km, it runs at 12 km per liter.

To find how much would 200 pens cost if 50 pens cost 20 rupees.

To find out much time it would take a person to go to school if he drives at 40 km/hr, and it takes 1 hour to reach him if he drives at 20 km/hr.

To find out the number of labor required to build up a house in a specific period.

**3. What is the formula for Unitary Method?**

To determine values about a single unit, Unitary Method is used. Unitary-method can be used to calculate measurements, etc. The unitary method is used to solve problems if there is variation in the given quantity. In this method, the value of one single unit is calculated first and then the value of the required quantities which can be obtained by arithmetic operations. The formula used to calculate the unitary method is

Value of one unit = [\frac{ \text {Total Value}}{\text{No. of Units}}]

**4. The cost of 5 notebooks is 200 Rs. Find:**

Several notebooks can be purchased with 400 Rs.

Cost of 20 notebooks

Given:

Cost of 5 notebooks= 200

Cost of 1 notebook= [\frac{200}{5}]=40

The number of notebooks that can be purchased with 40 Rupees= 1

The number of notebooks that can be purchased with 1 Rupee= 1/40

Therefore, the number of notebooks that can be purchased with 400 rupees= 1/40 x 400 =10

The cost of 1 notebook= 40 Rupees

The cost of 20 notebooks= 40 x 20= 800 Rupees