RS Aggarwal Solutions Class 7 Maths Chapter 2 Fractions: Download Free PDF

The term signifies a particular quantity of numbers that can denote a part of a whole object. The concept mainly deals with the divisions of a particular object into various segments.

Types of Fractions

Now that you have got a basic idea of what fractions denote, it is time to get familiar with the different types of fractions.

Components of Fractions

The primary two components constitute a fraction and they are the numerator and denominator. You will notice that a fraction is represented by two numbers, sometimes by three numbers, and there is a presence of a line between them. The numbers that are placed above the line are known as numerators and the numbers that are placed below the line are called denominators.

There are Seven Types of Fractions and They are:

1. Proper Fractions: The numerator of a fraction will be smaller in value than the denominator.

2. Improper Fractions: In this case, the numerators will be greater in value than the denominators.

3. Mixed Fractions: This type of fraction will consist of a natural number, which means any number that ranges from one to infinity, along with a fraction.

4. Like Fractions: In this case, the series of fractions will have the same denominators, which means the number placed below the line will be the same throughout the series of fractions.

5. Unlike Fractions: The series of fractions will have different denominators in each case.

6. Equivalent Fractions: There will be a series of fractions and the value of each of the fractions will be similar after simplification.

7. Unit Fractions: In the case of unit fractions, the numerator will be one and the denominator will be a positive integer, which means the value of the denominator will be greater than zero.

These are some of the basic concepts that the students must know before delving into solving the fraction equations and the rest of the thing that they have to do is simple calculations by adding, subtracting, multiplying, and dividing the numeric values.

Why Learning the Methods To Calculate Fractions is Important?

Learning the methods to calculate the fractions accurately, is very important for the students because it is considered one of the basic mathematical concepts that the students must learn in order to pursue their academic career in the future.

It is one of the equations that will help the students to solve more complicated equations in future because solving fraction problems teaches the students some important concepts related to the subtraction and division of numbers.

Why Refer To The Vedantu’s RS Aggarwal Solutions For Fractions (Exercise 2A) Exercise 2.1?

The RS Aggarwal solution for Class 7 Chapter 2 Fractions at Vedantu develops a solid conceptual base in students, which plays an important role in the latter stages of preparing for the competitive exams. The experts at Vedantu provided detailed solutions to the problems according to the CBSE prescribed method. The students can readily prepare all the concepts covered in the chapter much better and effectively and even crack the most demanding competitive exams like JEE Main, JEE Advanced NEET, AIMS, etc.

Contents of RS Aggarwal Class 7 Maths Exercise 2A Solution

RS Aggarwal Solutions Class 7 Maths Chapter 2 comprises four exercises that cover all the concepts on fractions. The concepts covered are: 

• Determination of the greater or lesser fraction

• Arranging fractions in ascending or descending order

• Addition of like and unlike fractions

• Subtraction of like and unlike fractions

• Word problems based on the above concepts with real-life application

Let Us Look Into Some Examples:

1. Compare the fractions $\dfrac{5}{8}$ and $2\dfrac{7}{14}$

Ans: The fractions are $\dfrac{5}{8}$ and $\dfrac{35}{14}$

L.C.M. of $8$ and $14 = 56$

Now changing the denominators into L.C.M.:

$\dfrac{5 \times 7}{8 \times 7} = \dfrac{35}{56}$

$\dfrac{35 \times 4}{14 \times 4} = \dfrac{140}{56}$

Now, $\dfrac{35}{56} < \dfrac{140}{56}$

$\therefore \dfrac{5}{8} < 2\dfrac{7}{14}$

2. Atul purchased $3\dfrac{3}{10}kg$ of cotton and sold $1\dfrac{7}{15}kg$ of cotton to the dealer. How much cotton is left with Atul?

Ans: Amount of cotton purchased by Atul $=  3310kg$

Amount of cotton sold to the dealer $= 1715kg$

Amount of cotton left with Atul $= 3\dfrac{3}{10} -1\dfrac{7}{15}kg$

$= \dfrac{33}{10} - \dfrac{22}{15}kg$

$= \dfrac{(33 \times 3) - (22 \times 2)}{30}$         (L.C.M. of 10 and 15 is 30)

$= \dfrac{99 -44}{30}$ 

$= \dfrac{55}{30}$

$= \dfrac{11}{6}$

$= 1\dfrac{5}{6}$