Easy Learning with RS Aggarwal Class 8 Mathematics Solutions for Chapter-5 Playing with Numbers

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All the Exercise questions with solutions in Chapter-5 Playing with Numbers are given below:

Exercise (Ex 5A) 5.1

Exercise (Ex 5B) 5.2

Exercise (Ex 5C) 5.3

Exercise (Ex 5D) 5.4

RS Aggarwal Solutions  Class 8 Solutions Chapter 5

• General Form of Numbers

If a two-digit number XY needs to be represented in general form, then

xy = 10x + y

Playing with 2 – Digit and 3 – Digit Numbers

• Numbers in General Form

The two digit number(xy) is written as xy = (10x ) + (1y) in its general form.

The three-digit number (xyz) is written as xyz = (100x) + (10y )+ z in its general form. 

• Reversing The 2 Digit Numbers And Adding Them

When you reverse a two-digit number and add with the number, the resulting number will be  divisible by 11 and the sum of the digits will be the quotient. 

For eg: The reverse of 24 is 42.

The sum of 24 and 42 = 66

On dividing the sum by 11, we get 66/11 = 6 = 2+4.

• Reversing The 2 Digit Numbers And Subtracting Them

When you reverse the two-digit numbers, the difference between the larger number f from the smaller number is divisible by 9, and the difference in the number of digits will be quotient. 

For example, the reverse of the number 36 is 63.

Now, 63 > 36

So, 63 – 36 = 27

On dividing the difference of the two numbers by 9, we get, 27/9 = 3 = 6−3

• Reversing The 3 Digit Numbers And Subtracting Them

When you reverse a three-digit number and the differences between the smaller number, and the larger number is perfectly divisible by 99, the difference between the first and third digit of the selected number will be the quotient. 

For example, the reverse of 142 is 241.

Now, 241 > 142.

241 – 142 = 99

Now,99/99 = 1 = 2 – 1

• Taking All The Combinations of 3 Digit Numbers And Adding Them

When any combinations of a three-digit number are taken, and you add them together, then the resulting number will be perfectly  divisible by 111

Let us take 153.

The various numbers that can be formed using the digits of 153 are 153, 135, 315, 531, 513 and 351.

The sum of 153, 135, 315, 531, 513, and 351 is 1998. 

Now,1998/111 = 18

• Divisibility Rules

Divisibility by 10

When the units digit of a number is 0 then the number is said to be divisible by 10.

For Instance,  1420 is divisible by 10. 133 is not divisible by 10 because it has 3 in its units place.

Divisibility by 5

When the units digit of a number is either 0 or 5 then it is said to be divisible by 5.

For instance, 155 is divisible by 5, but 122 is not divisible by 5.

Divisibility by 2

When the units digit of a number is either 2,4,6,8,0, it is divisible by 2.

For example, 12, 14, 78 are divisible by 2, but 33, 43, 55 are not.

Divisibility by 3

When the digits' sum is divisible by 3 , then the number is said to be divisible by 3. 

For eg:The sum of digits of 159= 1 + 5 + 9 = 15, which is divisible by 3. So, 159  is divisible by 3.

The sum of digits of 166 = 1 + 6 + 6 = 13, which is not divisible by 3. So, 166 is not divisible by 3.

Divisibility by 9

When the sum of the digits is divisible by 9 , then the number is said to be divisible by 9. 

For example, the sum of digits of 177 = 1+ 7 + 7 = 15, which is not divisible by 9. So, 177 is not divisible by 9.

The sum of digits of  693= 6 + 9 + 3 = 18, which is divisible by 9. So, 693 is divisible by 9.

Preparation Tips for RS Aggarwal Solutions Class 8 Ch 5

• Understand the example very well, which will help you to understand the pattern in the numbers. 

• Note down the different divisibility rules of the numbers which are crucial for solving problems of playing with numbers Class 8 Maths Chapter 5 Playing with Numbers. 

• Practice all the sums of Class 8 Maths RS Aggarwal chapter 5, ensuring you understand all the theories related to numbers. 

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Studying Playing With Numbers Chapter 5 will become a lot easier for the students of Class 8. The experts have formulated the solutions using simpler steps so that you can understand the basic concepts easily and can implement them during an exam.Download this PDF file today and make your study material complete.