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RS Aggarwal Solutions Class 6 Chapter-21 Concept of Perimeter and Area (Ex 21A) Exercise 21.1

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Last updated date: 23rd Apr 2024
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RS Aggarwal Solutions Class 6 Chapter-21 Concept of Perimeter and Area (Ex 21A) Exercise 21.1 - Free PDF

Free PDF download of RS Aggarwal solutions class 6 Chapter-21 concept of perimeter and area (Ex 21A) exercise 21.1 solved by expert mathematics teachers on Vedantu. All exercise 21.1 questions with solutions for class 6 RS Aggarwal to help you to revise the complete Syllabus and score more marks.

Class 6 Chapter-21 Concept of Perimeter and Area

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FAQs on RS Aggarwal Solutions Class 6 Chapter-21 Concept of Perimeter and Area (Ex 21A) Exercise 21.1

1. How Perimeter and Area have been Defined in (Ex 21A) Exercise 21.1 in Class 6 Chapter-21? 

In chapter 21 of class 6, the students are going to learn the Concept of Perimeter and the Area of an equilateral triangle. The term perimeter is defined as the sum of all sides of a closed figure. An equilateral triangle is defined as a triangle that owns all 3 of its sides in equal length. The perimeter of an Equilateral triangle remains equal to 3 times the total length of the side of a triangle. This is how it is defined for class 6 students. 

2. For which Shape Perimeter is measured in Class 6 Chapter-21 Concept of Perimeter and Area (Ex 21A) Exercise 21.1? 

A number of shapes are covered in Class 6 Chapter-21 Concept of Perimeter and Area (Ex 21A) Exercise 21.1. The students work on the perimeter of square, triangle, rectangle, equilateral triangle, regular octagon, regular pentagon, regular decagon, area of the square, area of the rectangle, finding a circle's diameter, the circumference of a circle, and much more to cover.  The students should keep in mind that all these subjects are interlinked to each other so they should focus on it from an initial level. 

3. If the Breadth and Length of a Rectangle Field are measured in the 7: 4 ratio, then the Field Fencing Cost will be 3300 i.e. Rupees 25 per Meter. You need to find the Field Dimension.

Fencing total cost is Rs 3300

The fencing rate is Rs 25/m

Field perimeter will be = fencing rate total cost = (Rs 3300Rs 25/m)=330025 m=132 m

If the breadth and length of the rectangular field will be respectively 7x and 4x

Field perimeter is = 2(7x + 4x) = 22x

This has been given that the field perimeter is 132 m.

∴ 22x=132⇒x=132/22=6∴ field length = (7 × 6) m=42 m field breadth = (4 × 6) m=24 m

4. Why should a Student select Vedantu for RS Aggarwal Solutions Class 6 Chapter-21 Concept of Perimeter and Area (Ex 21A) Exercise 21.1 - Free PDF? 

A student should select Vedantu for RS Aggarwal Solutions Class 6 Chapter-21 Concept of Perimeter and Area (Ex 21A) Exercise 21.1. Here, the students are able to avail themselves of varied benefits. Vedantu assures you of the authenticity of the notes available in its free PDF. The whole syllabus is prepared with care under the strict supervision of the Vedantu tutors. Besides excellent content quality, Vedantu helps the students in managing their time, releasing stress, and staying more focused on their studies. 

5. What are the Key Benefits of studying Class 6 Chapter-21 Concept of Perimeter and Area (Ex 21A) Exercise 21.1? 

A lot of benefits are associated with studying Class 6 Chapter-21 Concept of Perimeter and Area (Ex 21A) Exercise 21.1. By preparing the chapters of mathematics, students are able to gain their reasoning and logical skills at an early age. Getting apprised of all these conceptual things, the students will have a flair for cracking competitive exams in the upcoming years. This way, the students have a fair opportunity to excel themselves towards a bright future in their early years.