Vedantu’s RD Sharma Class 6 Chapter 3 Whole Numbers (Ex 3.1) Solutions - Free PDF
FAQs on RD Sharma Class 6 Solutions Chapter 3 - Whole Numbers (Ex 3.1) Exercise 3.1 - Free PDF
1. Where can I find reliable, step-by-step solutions for RD Sharma Class 6 Maths Chapter 3, Exercise 3.1?
You can find clear and accurate step-by-step solutions for all questions in RD Sharma Class 6 Maths Chapter 3, Exercise 3.1, on this platform. These solutions are prepared by subject matter experts to help you understand the correct method for solving each problem, aligning with the CBSE 2025-26 curriculum.
2. What is the main concept tested in RD Sharma Class 6, Chapter 3, Exercise 3.1?
Exercise 3.1 of RD Sharma Class 6 Maths Chapter 3 primarily tests your understanding of the fundamental concepts of whole numbers. This includes identifying whole numbers, finding the successor (the number that comes just after), and the predecessor (the number that comes just before) of a given whole number.
3. How do you find the successor of a given whole number as per the problems in Exercise 3.1?
To find the successor of any given whole number, you simply need to add 1 to it. For example, the successor of the whole number 99 is 99 + 1, which equals 100. This is a key operation for solving questions in this exercise.
4. What is the correct method to find the predecessor of a whole number?
The correct method to find the predecessor of a whole number is to subtract 1 from it. For instance, the predecessor of 543 is 543 - 1, which is 542. It is important to remember that this applies to all whole numbers except for one special case.
5. Are the solutions for the latest RD Sharma Class 6 Maths (2025-26 Edition) different for Chapter 3?
The core concepts of whole numbers, predecessors, and successors covered in Chapter 3 remain consistent across different editions of the RD Sharma textbook. Therefore, the methods and solutions for Exercise 3.1 are generally applicable for the 2025-26 edition as well as recent previous editions as the fundamental mathematical principles do not change.
6. What is the key difference between 'whole numbers' and 'natural numbers', and why is it important for this chapter?
The key difference is the number zero (0). Natural numbers are counting numbers starting from 1 (1, 2, 3,...). Whole numbers include all natural numbers plus zero (0, 1, 2, 3,...). This distinction is crucial because:
- The smallest whole number is 0.
- The smallest natural number is 1.
- Every natural number is a whole number, but not every whole number (specifically 0) is a natural number.
7. Why does the whole number 0 not have a predecessor in the set of whole numbers?
The predecessor of a number is found by subtracting 1. If we subtract 1 from 0, we get -1 (0 - 1 = -1). Since -1 is a negative integer and not a part of the set of whole numbers, we can conclude that 0 does not have a predecessor within the set of whole numbers. All other whole numbers have a predecessor that is also a whole number.
8. When a question asks for "three whole numbers occurring just before 10001", why is showing the steps important?
Simply listing the numbers might provide the right answer, but it doesn't demonstrate your understanding of the concept of a predecessor. For full marks in an exam, you should show the step-by-step process. This involves:
- Finding the first predecessor: 10001 - 1 = 10000
- Finding the second predecessor: 10000 - 1 = 9999
- Finding the third predecessor: 9999 - 1 = 9998
9. How do RD Sharma solutions for Chapter 3 build a stronger foundation compared to just using NCERT solutions?
While NCERT establishes the core concepts, RD Sharma provides a wider variety of problems with increasing difficulty. The detailed solutions for RD Sharma Chapter 3 help you to:
- Master the fundamentals like successor and predecessor through extensive practice.
- Gain confidence by tackling more complex variations of the same concept.
- Understand the application of properties of whole numbers in different scenarios, which prepares you better for school exams.
10. Is it possible for a whole number to be its own successor or predecessor?
No, it is not possible for a whole number to be its own successor or predecessor. The successor is always one greater than the number (n+1), and the predecessor is always one less (n-1). Since a number 'n' can never be equal to 'n+1' or 'n-1', a whole number cannot be its own successor or predecessor. This highlights a fundamental property of the number line.






















