$$\\text{Since PS is the angle bisector of }\\angle QPR \\\\ \\text{So by angle bisector theorem} \\\\ \\dfrac{QS}{SR}=\\dfrac{PQ}{PR} \\\\ \\Rightarrow \\dfrac{3}{SR}=\\dfrac{6}{8} \\\\ \\Rightarrow \\text{SR}=\\dfrac{8\\times 3}{6}=4\\text{ units}$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}