$$ \\\\ $$ Given, volume of right circular cone $$=\\dfrac{1}{3}\\pi {{r}^{2}}h =5376\\pi \\Rightarrow h =63$$ $$ \\\\ $$ So, height of frustum $$=\\left( 63-31.5 \\right)=31.5cm$$ $$ \\\\ $$ Hence, slant height of frustum, $$l{'} =\\sqrt{{{\\left( 16-8 \\right)}^{2}}+{{31.5}^{2}}} =\\sqrt{64+992.25} =32.5 $$ $$ \\\\ $$ So, required curved surface area $$=32.5\\left( 8 + 16 \\right)\\pi =780\\pi c{{m}^{2}}$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Geometry basics Quiz 1","text":" The sweet shop was asked to deliver 1910 sweets which includes two types of sweets - kaju barfi of dimensions 1 cm, 3 cm and 4 cm and besan barfi of dimensions 1cm, 3 cm and 3 cm. Both the types of sweets were packed together in 10 small square-shaped cartons with height 6 cm, each containing 75 kaju barfi. How many similar cartons would be required to pack 810 kaju barfi only?","comment":{"@type":"Comment","text":" Find the volume of one kaju barfi, one besan barfi, and the carton's volume first, then multiply by the number of sweets packed in each carton to get the length and width of the carton."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 4","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" 6","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" 7","position":2}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 5","position":3,"answerExplanation":{"@type":"Comment","text":"The volume of each kaju barfi $$= 1\\times 3\\times 4 c{{m}^{3}}~=12 c{{m}^{3}}$$ $$ \\\\ $$ Volume of each besan barfi $$= 1 \\times 3 \\times 3 c{{m}^{3}} = 9 c{{m}^{3}}$$ $$ \\\\ $$ Now, let the length and breadth of the cartons be$$x cm$$ $$ \\\\ $$ Then, volume of the cartons $$=6{{x}^{2}}~c{{m}^{3}}$$ $$ \\\\ $$ 1910 sweets were packed in 10 cartons $$ \\\\ $$ $$\\Rightarrow$$ 191 sweets were packed in each carton $$ \\\\ $$ $$\\Rightarrow$$ 116 besan barfi and 75 kaju barfi were packed in each carton $$ \\\\ \\therefore 6{{x}^{2}}~=12\\times 75+9\\times 116 \\\\ \\Rightarrow {{x}^{2}}~=150+174=324 \\Rightarrow x=18 \\\\ $$ So, the length and breadth of each carton is $$18 cm$$. $$ \\\\ $$ So, volume of each carton $$= 6\\times 18\\times 18 c{{m}^{3}}=1944 c{{m}^{3}}$$ $$ \\\\ $$ In each carton, $$\\dfrac{1944}{12}=162$$ kaju barfi can be packed $$ \\\\ $$ $$\\therefore$$ 810 Kaju barfi can be packed in $$\\dfrac{810}{162} \\text{cartons} = 5 \\text{cartons}$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}