$$ \\\\ $$ The area of the whole sheet is $${{16}^{2}}=256\\,sqcm$$ $$ \\\\ $$ The area of the circle is $$\\pi {{4}^{2}}=50.26\\,sqcm$$ $$ \\\\ $$ The area of the rectangle is $$4\\times 5=20\\,sqcm$$ $$ \\\\ $$ The area of the remaining part $$= ($$area of whole sheet$$) - 3($$area of circle$$) - ($$area of rectangle$$)$$ $$ \\\\ =\\left( 256 \\right)-3\\left( 50.26 \\right)-\\left( 20 \\right) =85.2\\,sqcm$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Area and circumference of a circle Quiz 1","text":" Find the area of a circle whose radius is a root of the equation $${{x}^{2}}-\\left( 4-\\sqrt{3} \\right)x-\\sqrt{48}=0$$.","comment":{"@type":"Comment","text":" First find the roots of the given equations , choose the appropriate radius and then use the formula to calculate the area of the circle."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$28.27$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$78.53$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$19.63$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$50.26$$","position":0,"answerExplanation":{"@type":"Comment","text":" $${{x}^{2}}-\\left( 4-\\sqrt{3} \\right)x-\\sqrt{48}=0\\,\\,\\Rightarrow \\,{{x}^{2}}-\\left( 4-\\sqrt{3} \\right)x-{{4\\sqrt{3}}^2}=0 \\\\ \\Rightarrow \\,\\left( x-4 \\right)\\left( x+\\sqrt{3} \\right)=0 \\\\ $$ The roots are $$4,\\,-\\sqrt{3}$$. But radius cannot be negative. Hence $$r=4$$ $$ \\\\ $$ Area of circle $$=\\pi {{r}^{2}} \\\\ =\\pi {{4}^{2}} =50.26$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Area and circumference of a circle Quiz 1","text":" A boy is riding a bicycle at a speed of $$10\\,cm/s$$ which has a wheel diameter of $$40\\,cm$$. How many revolutions does each wheel make in $$2\\,\\min $$. ","comment":{"@type":"Comment","text":" First calculate the total distance travelled and circumference of the wheel and then use the formula to calculate the number of revolutions."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$226278$$ rev","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$565695$$ rev","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$157.13$$ rev","position":2}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$150852$$ rev","position":3,"answerExplanation":{"@type":"Comment","text":"First let us calculate the distance traveled in $$2\\,\\min $$. $$ \\\\ $$ $$\\Rightarrow 10\\times 2\\times 60 \\,cm$$ $$ \\\\ $$ radius $$=\\dfrac{40}{2} = 20 $$ $$ \\\\ $$ Circumference of the wheel is $$ 2\\pi r \\Rightarrow 2 \\times \\dfrac{22}{7} \\times 20 \\Rightarrow 125.71 $$ $$ \\\\ $$ Number of revolutions $$= \\text{distance} \\times \\text{circumference} \\\\ = 10 \\times {2} \\times {60} \\times 125.71 = 150852rev$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Area and circumference of a circle Quiz 1","text":" A garden is in the shape of a ring with an outer radius of $$10m$$ and an inner radius of $$8m$$. Fertilizer is going to be purchased for the garden and each bag of fertilizer can cover $$3{{m}^{2}}$$ of area. How many bags of fertilizer should be purchased to have enough to cover the garden?","comment":{"@type":"Comment","text":" First find the area of the garden using an area of circle with outer diameter and inner diameter and then use the appropriate formula to calculate the required number of bags."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$34$$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$35$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$37$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$38$$","position":2,"answerExplanation":{"@type":"Comment","text":" The area of the garden $$=$$ area of circle with outer diameter $$–$$ area of circle with inner diameter $$=\\left( \\pi {{\\left( 10 \\right)}^{2}} \\right)-\\left( \\pi {{\\left( 8 \\right)}^{2}} \\right)$$ $$ \\\\ $$ Now it is given that each fertilizer bag can cover $$3{{m}^{2}}$$ $$ \\\\ $$ Hence, the number of bags $$=\\dfrac{\\text{area of the total garden}}{\\text{area covered by each bag}} \\\\ =\\dfrac{\\left( \\pi {{\\left( 10 \\right)}^{2}} \\right)-\\left( \\pi {{\\left( 8 \\right)}^{2}} \\right)}{3}\\,=\\dfrac{36\\pi }{3}=38\\,bags$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Area and circumference of a circle Quiz 1","text":" A barrel of whiskey is being rolled up a $$100\\,foot$$ ramp. The barrel has to be rolled $$30$$ times to get up the ramp. What is the diameter of the circular base of the barrel?","comment":{"@type":"Comment","text":" First find the total circumference in terms of radius of the base of the barrel and then equate it to the length of the ramp to find the required diameter."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 0.96 ft","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" 0.53 ft","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" 0.48 ft","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" 1.06 ft","position":1,"answerExplanation":{"@type":"Comment","text":" $$ \\\\ $$ Let the radius of barrel be $$r$$ $$ \\\\ $$ The circumference of the barrel is $$=2\\pi r$$ $$ \\\\ $$ The barrel is rolled 30 times, hence total circumference is $$=2\\pi r\\times 30$$ $$ \\\\ $$ The length of the ramp is $$100\\,foot$$. $$ \\\\ \\therefore 2\\pi r\\times 30=100 \\\\ \\Rightarrow r=\\dfrac{100}{30\\times 2\\pi } \\\\ \\Rightarrow r=0.53 \\\\ $$ Hence, the diameter is $$2r$$ $$ \\\\ \\therefore d=1.06\\,ft$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}