","comment":{"@type":"Comment","text":" First find the total production for each company from the graph and then find out the difference between them."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$29,00,000$$ ","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$2,90,000$$ ","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$2,70,000$$ ","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$27,00,000$$ ","position":0,"answerExplanation":{"@type":"Comment","text":"Total production by the company A $$ = \\left( {4 + 3 + 8 + 8 + 8 + 7 + 8 + 12} \\right) \\times {10^5} = 58 \\times {10^5}$$ $$ \\\\ $$ Total production by the company B $$ = \\left( {1 + 1 + 1 + 2 + 3 + 5 + 7 + 11} \\right) \\times {10^5} = 31 \\times {10^5}$$ $$ \\\\ $$ Difference in total production of the both companies $$ = 58 \\times {10^5} - 31 \\times {10^5} = 27 \\times {10^5}$$ that is $$27,00,000$$ ","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Interpreting graphs Quiz 1","text":" The following graph shows the growth of potatoes over a period of seven years from $$2009 - 2016$$. You have to find which year the potato growth was maximum. $$ \\\\ $$ ","comment":{"@type":"Comment","text":" For maximum growth find the peak point of the graph"},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$2010$$ ","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$2013$$ ","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$2015$$ ","position":2}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" None of these","position":3,"answerExplanation":{"@type":"Comment","text":"As we know that the potato growth is maximum where the graph is at its peak $$\\text{(maximum)}$$ and we can see that in $$2011$$ the graph is at its peak and shows a growth of $$75$$ potatoes.","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Interpreting graphs Quiz 1","text":" Study the below graph showing the data of human resources over the years and then tell the number of human resources in $$1999$$ was what percent of the initial year? $$ \\\\ $$
","comment":{"@type":"Comment","text":" Find data from the graph and then the percentage. If we have to calculate $x$ in comparison to percent of $y$ then it is given as $\\dfrac{x}{y} \\times 100$ "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$200\\% $$ ","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$400\\% $$ ","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$50\\% $$ ","position":2}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$450\\% $$ ","position":3,"answerExplanation":{"@type":"Comment","text":"Human resource on $$1999 = 225$$ $$ \\\\ $$ Human resource on initial year, i.e. $$1993 = 50$$ $$ \\\\ $$ So, required percentage $$ = \\dfrac{{225}}{{50}} \\times 100 = 450\\% $$ ","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Interpreting graphs Quiz 1","text":" For the same graph of human resource shown in the previous question, tell the change in percentage from $$1996\\;{\\text{to}}\\;1997$$ ","comment":{"@type":"Comment","text":" Percent change is given as $\\dfrac{{a - b}}{b} \\times 100,\\;{\\text{where}}\\;a\\;{\\text{and}}\\;b$ are changed value, original value."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$10\\% $$ ","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$50\\% $$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$200\\% $$ ","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$100\\% $$ ","position":2,"answerExplanation":{"@type":"Comment","text":"Percentage change from year $$1996\\;{\\text{to}}\\;1997$$ is given as $$ \\\\ = \\dfrac{{200 - 100}}{{100}} \\times 100 = 100\\% $$ ","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Interpreting graphs Quiz 1","text":" Study the graph below showing the profit percentage of two companies over years and then tell the expenditure of company B in the year $$1999$$ if its income for the same year was $$Rs.\\;2,60,000$$ $$ \\\\ $$
","comment":{"@type":"Comment","text":" Use the formula, Income $ = $ Expenditure $ + $ Profit, and express the profit in terms of expenditure as the profit percent is given in the graph."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$Rs.\\;1,00,000$$ ","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$Rs.\\;1,50,000$$ ","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" None of the above","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$Rs.\\;2,00,000$$ ","position":1,"answerExplanation":{"@type":"Comment","text":"We know that $$I = E + P,\\;{\\text{where}}\\;I,\\;E\\;{\\text{and}}\\;P$$ are income, expenditure and profit respectively $$ \\\\ $$ Also we have profit percentage of company B in the year $$1999 = 30\\% $$ $$ \\\\ $$ That is, $$P = \\dfrac{{30}}{{100}} \\times E$$ $$ \\\\ $$ Putting this in the above formula, we get $$ \\Rightarrow I = E + P \\\\ \\Rightarrow 260000 = E + \\dfrac{{3E}}{{10}} \\\\ \\Rightarrow 260000 = \\dfrac{{13E}}{{10}} \\\\ \\Rightarrow E = \\dfrac{{260000 \\times 10}}{{13}} \\\\ \\Rightarrow E = Rs.\\;2,00,000 \\\\ $$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}