$$ \\text{For }g\\ge 0, {{g}_{\\min }}=1$$ After making changes in the cosecant function according to question, $$\\\\ p=5\\text{ }cosec\\left( x+1 \\right) \\\\ $$ $$\\\\ {{p}_{\\min }}=5\\\\$$ For keeping same minimum value, we need to shift the curve downward vertically by: $${{p}_{\\min }}-{{g}_{\\min }}=5-1=4$$ ","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing trig functions: sec, scs, cot Quiz 1","text":" A wave is transmitted through the vacuum. The function of the wave is calculated to be $$f(x)=3\\sin 2x$$ for a time period. For what value or values of $$x$$ does $$f(x)$$ have a relative maximum? ","comment":{"@type":"Comment","text":" Draw the curve $\\sin \\text{ 2x}$ and compare it with sin x curve. Relative maximum for a time period of the sine curve is the maximum value for this curve."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{\\pi }{3},\\dfrac{\\pi }{4}$$ ","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{\\pi }{2}$$","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{\\pi }{6},\\dfrac{\\pi }{4},\\dfrac{\\pi }{3}$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$\\dfrac{\\pi }{4}$$","position":0,"answerExplanation":{"@type":"Comment","text":" Draw the curve $$f\\left( x \\right)$$ as we need to decide the relative maximum. Seeing the option, we find that x are given for greater than 0. Thus, plot the $$f\\left( x \\right)$$ for $$x\\ge 0 \\\\ $$
$$ \\\\ $$The relative maximum point of this curve is at the highest point. For the above curve the maximum point is at midpoint of $$0,\\dfrac{\\pi }{2}$$. The value of 'x' for relative maximum is x=$$\\dfrac{1}{2}\\left( \\dfrac{\\pi }{2} \\right) \\\\=\\dfrac{\\pi }{4}$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing trig functions: sec, scs, cot Quiz 1","text":" A student was asked to graph the function of $$\\dfrac{1}{3}\\cot \\left( \\dfrac{1}{2}x \\right)$$ . Given that the teacher asked the student to graph the function in the interval $$[0,3\\pi ]$$, calculate the $$x-$$intercepts of the function. ","comment":{"@type":"Comment","text":" The x intercept of the graph means the point where $y=0$. Draw the curve of $\\dfrac{1}{3}\\cot \\left( \\dfrac{1}{2}x \\right)$ as mentioned in the question. Find the x intercept of cot x and then start comparing it for $\\dfrac{1}{3}\\cot \\left( \\dfrac{1}{2}x \\right)$ ."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$x=\\pi ,2\\pi $$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$x=2\\pi ,3\\pi $$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$x=1.061,7.344$$","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$x=\\pi ,3\\pi $$","position":2,"answerExplanation":{"@type":"Comment","text":" $$ \\text{Let }f\\left( x \\right)=\\dfrac{1}{3}\\cot \\left( \\dfrac{x}{2} \\right)\\\\ \\text{x-intercepts are formed at }f\\left( x \\right)=0 \\\\ \\Rightarrow \\dfrac{1}{3}\\cot \\left( \\dfrac{x}{2} \\right)=0 \\\\ \\Rightarrow \\cot \\left( \\dfrac{x}{2} \\right)=0 \\\\ \\Rightarrow \\dfrac{x}{2}=\\dfrac{\\pi }{2},\\dfrac{3\\pi }{2} \\\\ \\Rightarrow x=\\pi ,3\\pi$$
","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing trig functions: sec, scs, cot Quiz 1","text":" For a function $$\\sec (x-1)+1$$ with $$y\\ge 0$$, a new secant function has twice the amplitude, the frequency is twice as well as a vertical shift of 3 units more that of the previous function. Calculate the possible horizontal shift. ","comment":{"@type":"Comment","text":" Find the x – coordinate corresponding to minimum y – coordinate of both functions through graphs. The difference between their x -coordinate is required horizontal shift."},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$1$$unit","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$1.5$$units","position":2},{"@type":"Answer","encodingFormat":"text/html","text":" $$3$$units ","position":3}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$0.5$$units","position":1,"answerExplanation":{"@type":"Comment","text":" $$\\text{Draw the diagram of y}=\\sec (x-1)+1\\text{for }y\\ge 0 \\\\ $$.
$$ \\\\ $$According to question the new secant function will be Y=$$2\\sec \\left( 2x-1 \\right)+4\\\\$$ Draw the diagram of Y=$$2\\sec \\left( 2x-1 \\right)+4 \\text{for }y\\ge 0 \\\\ $$.
$$ \\\\ \\text{Taking for a single period,}\\\\ \\text{X – coordinate of }y=\\sec \\left( x-1 \\right)+1 \\text{at }y=2 \\text{is 1}\\\\ \\text{X – coordinate of Y}=2\\sec \\left( 2x-1 \\right)+4 \\text{at }Y=6 \\text{is }\\dfrac{1}{2}\\\\$$ Horizontal Shift is difference of x – coordinates that is $$1-\\dfrac{1}{2}=\\dfrac{1}{2}=0.5$$","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]},{"@type":"Question","eduQuestionType":"Multiple choice","learningResourceType":"Practice problem","educationalLevel":"beginner","name":"Graphing trig functions: sec, scs, cot Quiz 1","text":" Identify the below function a student drew.
","comment":{"@type":"Comment","text":" Solve the questions option wise. Draw inference from the given points of the graph and check option wise for each inference. In such a question, take care of radian and degree, try to solve using radian. "},"encodingFormat":"text/markdown","suggestedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$f(x)=\\dfrac{1}{\\sqrt{3}}\\cot \\left( 2x-\\dfrac{5\\pi }{2} \\right)+1$$","position":0},{"@type":"Answer","encodingFormat":"text/html","text":" $$f(x)=\\sin (\\cos (x))$$","position":1},{"@type":"Answer","encodingFormat":"text/html","text":" $$f(x)=3\\tan \\left( 2x-\\dfrac{5\\pi }{2} \\right)+1$$ ","position":2}],"acceptedAnswer":[{"@type":"Answer","encodingFormat":"text/html","text":" $$f(x)=\\sqrt{3}\\cot \\left( 2x-\\dfrac{5\\pi }{2} \\right)+1$$","position":3,"answerExplanation":{"@type":"Comment","text":"For this, take an option wise approach. From the given graph at x=0, y=1, Checking relation for every option. $$\\\\ \\text{Option A: }\\dfrac{1}{\\sqrt{3}}\\cot \\left( 2x-\\dfrac{5\\pi }{2} \\right)+1=\\dfrac{1}{\\sqrt{3}}\\cot \\left( -\\dfrac{5\\pi }{2} \\right)+1=0+1=1\\\\ \\text{Option B: }\\sin (\\cos (x))=\\sin \\left( \\cos \\left( 0 \\right) \\right)=\\sin \\left( 1 \\right)\\ne 1\\\\ \\text{Option C: }3\\tan \\left( 2x-\\dfrac{5\\pi }{2} \\right)+1=3\\tan \\left( -\\dfrac{5\\pi }{2} \\right)+1=\\infty \\ne 1\\\\ \\text{Option D:} \\sqrt{3}\\cot \\left( 2x-\\dfrac{5\\pi }{2} \\right)+1=\\sqrt{3}\\cot \\left( -\\dfrac{5\\pi }{2} \\right)+1=0+1=1\\\\ \\text{From this step, option B and C are rejected.}\\\\ \\text{Second point is for }y=0,\\text{ x=}\\dfrac{19\\pi }{12}\\\\$$ Here, we will only check for option A and D. Put y=0 and find x and then compare with above relation. $$\\\\ \\text{Option A:}\\\\ \\dfrac{1}{\\sqrt{3}}\\cot \\left( 2x-\\dfrac{5\\pi }{2} \\right)=-1 \\\\ 2x-\\dfrac{5\\pi }{2}={{\\cot }^{-1}}\\left( -\\sqrt{3} \\right) \\\\ 2x-\\dfrac{5\\pi }{2}=\\dfrac{5\\pi }{6} \\\\ 2x=\\dfrac{10\\pi }{3} \\\\ x=\\dfrac{5\\pi }{3} \\\\ \\text{Option D: }\\\\ \\sqrt{3}\\cot \\left( 2x-\\dfrac{5\\pi }{2} \\right)=-1 \\\\ 2x-\\dfrac{5\\pi }{2}={{\\cot }^{-1}}\\left( -\\dfrac{1}{\\sqrt{3}} \\right) \\\\ 2x-\\dfrac{5\\pi }{2}=\\dfrac{2\\pi }{3} \\\\ 2x=\\dfrac{19\\pi }{6} \\\\ x=\\dfrac{19\\pi }{12} \\\\$$ Therefore, option D matches with the fig.","encodingFormat":"text/html"},"comment":{"@type":"Comment"}}]}]}